#include <math.h>
#include<stdio.h>
main()
{
int n;
double rate;
double capital;
double deposit;
printf("Please enter rate, year, capital:");
scanf("%1f,%d,%1f", &rate, &n, &capital);
deposit = capital * pow(1+rate,n);
printf("deposit = %f\n", deposit);
}
我想用它算存款问题,但输出的不知是几进制的数字还带负号. 我用的是TC2.0

scanf("%1f,%d,%1f", &rate, &n, &capital);把我加下划线的1改成L,输入时小写L与1相同,很难发现.

#include <math.h>
#include<stdio.h>
main()
{
int n;
double rate;
double capital;
double deposit;
printf("Please enter rate, year, capital:");
scanf("%1f,%d,%1f", &rate, &n, &capital);/*scanf("%lf%d%lf", &rate, &n, &capital);*/
deposit = capital * pow(1+rate,n);
printf("deposit = %lf\n", deposit);
}

printf("deposit = %f\n", deposit);
printf("deposit = %lf\n", deposit);
也许是这里

#include <math.h>
#include<stdio.h>
main()
{
int n;
double rate;
double capital;
double deposit;
printf("Please enter rate, year, capital:");
scanf("%lf%d%lf", &rate, &n, &capital);
deposit = capital * pow(1+rate,n);
printf("deposit = %lf\n", deposit);
}

deposit = capital * pow(1+rate,n);这里是什么意思没看懂？

我不是学C的不清楚

我习惯用cout