这是俺在MSDN上查到的:
<utility>
namespace std {
// TEMPLATE CLASSES
template<class T, class U>
struct pair;
// TEMPLATE FUNCTIONS
template<class T, class U>
pair<T, U> make_pair(const T& x, const U& y);
template<class T, class U>
bool operator==(const pair<T, U>& x, const pair<T, U>& y);
template<class T, class U>
bool operator!=(const pair<T, U>& x, const pair<T, U>& y);
template<class T, class U>
bool operator<(const pair<T, U>& x, const pair<T, U>& y);
template<class T, class U>
bool operator>(const pair<T, U>& x, const pair<T, U>& y);
template<class T, class U>
bool operator<=(const pair<T, U>& x, const pair<T, U>& y);
template<class T, class U>
bool operator>=(const pair<T, U>& x, const pair<T, U>& y);
namespace rel_ops {
template<class T>
bool operator!=(const T& x, const T& y);
template<class T>
bool operator<=(const T& x, const T& y);
template<class T>
bool operator>(const T& x, const T& y);
template<class T>
bool operator>=(const T& x, const T& y);
};
};
Include the STL standard header <utility> to define several templates of general use throughout the Standard Template Library.
Four template operators -- operator!=, operator<=, operator>, and operator>= -- define a total ordering on pairs of operands of the same type, given definitions of operator== and operator<.
If an implementation supports namespaces, these template operators are defined in the rel_ops namespace, nested within the std namespace. If you wish to use these template operators, write the declaration:
using namespace std::rel_ops;
which promotes the template operators into the current namespace.