题目:输入一个不多于5位的正整数
要求:1 求他是几位数
2 分别输出每一个数字
3 按逆序输出各位数字
例如 原数为321 应输出123

以下是我写的程序:
#include<stdio.h>
#include<math.h>
void main()
{
long int num;
int indiv,ten,hundred,thousand,ten_thousand,place;
printf("请输入一个整数(0~99999):");
scanf("%ld",&num);
if (num>9999)
place=5;
else if (num>999)
place=4;
else if (num>99)
place=3;
else if (num>9)
place=2;
else place=1;
printf("位数=%d\n",place);
printf("每位数字为:");
ten_thousand=num/10000;
thousand=(int)(num-ten_thousand*10000)/1000;
hundred=(int)(num-ten_thousand*10000-thousand*1000)/100;
ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;
indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);
switch(place)
{case5:printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv);
printf("\n 反序数字为:");
printf("%d%d%d%d%d\n",indiv,ten,hundred,thousand,ten_thousand);
break;
case4:printf("%d,%d,%d,%d",thousand,hundred,ten,indiv);
printf("\n 反序数字为:");
printf("%d%d%d%d\n",indiv,ten,hundred,thousand);
break;
case3:printf("%d,%d,%d",hundred,ten,indiv);
printf("\n 反序数字为:");
printf("%d%d%d\n",indiv,ten,hundred);
break;
case2:printf("%d,%d",ten,indiv);
printf("\n 反序数字为:");
printf("%d%d\n",indiv,ten);
break;
case1:printf("%d",indiv);
printf("\n 反序数字为:");
printf("%d\n",indiv);
break;
}
}

请各位帮我看一下为什么只能显示出位数而其他两项显示不出来

[此贴子已经被作者于2006-12-15 23:49:48编辑过]