不要拿去交,输出格式不同,通不过的.
#include<stdio.h>
#include<string.h>
#define M 53
const int a[53]={ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,-100, 0,
-50,-2,-3,-4,-5,-6,-7,-8,-9,-10,-20, -30,-40,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0,100, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0};//52牌中各张牌的分数
const char *b="01234567890JQK"; //13种点数
const int c[4]={6,3,4,5}; //4种花色的ASCII码
const int h_total=-194; //所有13张红心牌的总分数,用于判断玩家是否拿了所有13张红心
int encode(char *s) //将扑克牌编号1-52(编码)
{
int m,p;
if(*s=='S')
m=0;
else if(*s=='H')
m=1;
else if(*s=='D')
m=2;
else if(*s=='C')
m=3;
if(strlen(s)==2) //输入的字符串只有2个或3个字符两种
{
p=*(s+1)+1-'1';
return m*13+p;
}
else
{
p=*(s+2)+1-'1'+10*(*(s+1)+1-'1');
return m*13+p;
}
}
void decode(int a,char *s) //s[0]存放花色,s[1]和s[2]存放点数,仅当X10点时才用上s[2]
{
int t;
t=(a-1)/13;
*s=c[t];
t=(a-1)%13+1;
if(t==10)
{
*(s+1)='1';
*(s+2)='0';
*(s+3)='\0';
}
else
{
*(s+1)=b[t];
*(s+2)='\0';
}
}
void count(int (*p)[M],int *s) //p[][]用于传递4位玩家的牌,s[]用于存储4家的分数
{
int s_score,h_score,d_score,c_score;
int i,j,total;
for(i=0;i<4;i++)
{
total=0;
s_score=0; //存放黑桃的分数
h_score=0; //存放红心的分数
d_score=0; //存放方块的分数
c_score=1; //存放梅花的分数
for(j=1;j<=p[i][0];j++)
{
if(p[i][j]>=1 && p[i][j]<=13)
s_score+=a[p[i][j]];
else if(p[i][j]>=14 && p[i][j]<=26)
h_score+=a[p[i][j]];
else if(p[i][j]>=27 && p[i][j]<=39)
d_score+=a[p[i][j]];
else if(p[i][j]==49)
c_score=2;
}
if(h_score==h_total) //如果玩家拿了所有13张红心
h_score=200;
if(h_score==200 && s_score==-100 && d_score==100)
total=500; //若 S12、D11 皆在吃下所有红心牌之一家，则此玩家得 +500 分
else
total=h_score+s_score+d_score;
if(total==0 && c_score==2) //若持有 C10 的玩家只有该张牌而没有任何其它牌则得 +50 分
total=50;
else
total*=c_score; //除了 C10 还有其它计分牌，则将其它计分牌所得分数加倍计算
s[i]=total;
}
}
int main(void)
{
int player[4][M]; //play[i][0]存放玩家i+1牌的张数
int score[4];
int i,j;
char temp[10]; //临时存储输入的字符串
while(1)
{
for(i=0;i<4;i++)
{
printf("Player%d:",i+1);
scanf("%d",&player[i][0]);
for(j=1;j<=player[i][0];j++)
{
scanf("%s",temp);
player[i][j]=encode(temp);
}
}
if((player[0][0] || player[1][0] || player[2][0] || player[3][0])==0)
break;
printf("\n");
for(i=0;i<4;i++)
{
printf("the puker of player%d:",i+1);
for(j=1;j<=player[i][0];j++)
{
decode(player[i][j],temp);
printf("%4s",temp);
}
printf("\n");
}
count(player,score);
printf("\n");
for(i=0;i<4;i++)
printf("The score of player%d:%4d\n",i+1,score[i]);
}
return 0;
}
