制作一个函数表实现以下内容
0<=x<=3.1415926
实现以下结果 ：
x sin(x) cos(x) tan(x) exp(x)
0.000000 0.000000 1.000000 0.000000 1.000000
0.157080 0.156435 0.987688 0.158385 1.170089
0.314160 0.309018 0.951056 0.324921 1.369109
0.471240 0.453991 0.891006 0.509527 1.601979
0.628320 0.587786 0.809016 0.726545 1.874459
0.785400 0.707108 0.707105 1.000004 2.193284
0.942480 0.809018 0.587783 1.376383 2.566338



我只能一次实现一个 全部的做不出来
#include <stdio.h>
#include <math.h>
int main(void)
{
double result, x = 0.000000;
result = sin(x);
result = cos(x);
result = tan(x);
printf("The sin() of %lf is %lf\n", x, result);
printf("The cosine of %lf is %lf\n", x, result);
printf("The tan of %lf is %lf\n", x, result);
return 0;
}


请教各位了 谢谢了

不错嘛

#include"math.h"
main()
{float x;
for(x=0;x<=3.1415926;x=x+0.157080)
printf("%f %f %f %f %f\n",x,sin(x),cos(x),tan(x),exp(x));

}
看人家小姑娘做的.......

#include"math.h"
main()
{float x;
for(x=0;x<1;x=x+0.157080)
printf("%f %f %f %f %f\n",x,sin(x),cos(x),tan(x),exp(x));
}

sin(x),cos(x),tan(x),exp(x)[em09]