用户输入一周工作多少工时，并能计算这名员工的总收入和纯收入。假设雇员一小时报酬为￥10，询问用户是否加班，如果是，付给￥15/小时。如果总工资小于等于300，应缴10%税，如果小于=1000，大于300，应缴15%税，如果大于1000，应缴25%税。输出雇员总收入和纯收入

#include <stdio.h>
main()
{ int i,huor=10,huors=15;
int j;
int sum=0,sum1=0;
printf("Input your number");
scanf("%i",&i);
printf("shi fou jiaban?Y or N");
scanf("%i",&j);
if (j==0)
sum=i*huors;
else
sum=i*huor;
printf("%i\n",sum);
if(sum>0&&sum<300)
printf("%i",sum1==sum*0.9);
else if(sum>300&&sum<1000)
printf("%i",sum1==sum*0.85);
else if (sum>1000)
printf("%i",sum1==sum*0.75);
getchar();
return 0;
}

scanf("%i",&j);
if (j==0)


j不是要Y N 吗????

没有输入加班时间的语句啊

我小改了下你看看

#include <stdio.h>
main()
{ int i,k,huor=10,huors=15;
char j;
float sum=0;
printf("Input your number");
scanf("%d",&i);
printf("shi fou jiaban?Y or N");
fflush(stdin);
scanf("%c",&j);

if (j=='y' || j=='Y')
{
printf("jia ban shi jian:");
scanf("%d",&k);
sum=i*huor+k*huors;
}
else
{
sum=i*huor;
}
printf("%.2f\n",sum);
if(sum>0&&sum<300)
printf("%.2f",sum*=0.9);
else if(sum>300&&sum<1000)
printf("%.2f",sum*=0.85);
else if (sum>1000)
printf("%.2f",sum*=0.75);
}

#include<stdio.h>
void main()
{int time,money,real,add;
printf("How many time are you work a week:");
scanf("%d",&time);
printf("How many time are you add?");
scanf("%d",&add);
money=10*time+15*add;
if(money<300)
real=(money*9)/10;
else if(money>=300&&money<=1000)
real=(money*85)/100;
else real=(money*75)/100;
printf("all money=%d,real money=%d",money,real);
printf("\n");
}

#include <stdio.h>
#include <conio.h>
int main(void)
{
float weekWorkTime=0;
float addWorkTime=0;
clrscr();

printf("请输入一周工作工时:");
scanf("%f",&weekWorkTime);
getchar();

printf("请输入加工工时:");
scanf("%f",&addWorkTime);
getchar();

printf("总收入:%.1f元\n",(weekWorkTime*10+addWorkTime*15));

if((weekWorkTime*10+addWorkTime*15)<=300)
printf("纯收入:%.1f元\n",(weekWorkTime*10+addWorkTime*15)*(0.1));
if((weekWorkTime*10+addWorkTime*15)>300
&& (weekWorkTime*10+addWorkTime*15)<=1000)
printf("纯收入:%.1f元\n",(weekWorkTime*10+addWorkTime*15)*(0.15));
if((weekWorkTime*10+addWorkTime*15)>1000)
printf("纯收入:%.1f元\n",(weekWorkTime*10+addWorkTime*15)*(0.25));

getch();
}

#include"stdio.h"
void main()
{
int salary(hour,flag);
int hour;
char flag;
int jiaban;
int gongzi;
printf("请输入工作时间：")；
scanf("%d",&hour);
printf("您加班了吗 ，是请y,否则请选N");
scanf("%c",&flag);
printf("您的这周工资是%d",salary(hour,flag));
}
调用函数没有写。参考上面的就可以了

5楼的有道理,我看是这个意思的,还好加班和不加班的分开的,还是要看自己怎么理解.
4楼的有道理,但是你的意思是加班的和不加班的不是很清楚,还有我也看不动怎么会事,
6楼的有道理,需要改一处"clrscr()",改成"getchar" 谢谢,OK

7楼的我实在没有办法去看懂,要不你自己要改改,我改了还是没有改成功啊

#include <stdio.h>
main(){
int t;
float m,n;
char a;

printf("your work time(hour)\n");
scanf("%d",&t);
getchar();

printf("extral working?(y/n)\n");
scanf("%c",&a);
if(a=='y') m=15*t;
else m=15*t;

n=(m<=300l?(m*0.9):(m<=1000l?(m*0.85):(m*0.75)));

printf("total--%.2f ** actual--%.2f\n",m,n);

}

这个怎么样......