1.

请用JAVA语言实现函数并对之进行测试

   x  (x<1)

y= 2x-1  (1<=x<10)

   3x-11 (x>=10

2.使用java.util.Calendar类制作一个程序用“YYYY/MM/DD HH:MM:SS”格式显示当前日期和时间。

[此贴子已经被作者于2005-5-10 14:19:58编辑过]

晕第一题用Swich()函数或者其他函数就可以做,很简单!
第二题,偶不会,偶学Java才不久

[CODE]

import java.util.Calendar;

public class DisplayDateTime { public static void main(String args[]) { Calendar c=Calendar.getInstance(); System.out.println(c.get(Calendar.YEAR) + "/" + c.get(Calendar.MONTH) + "/" + c.get(Calendar.DAY_OF_MONTH) + " " + c.get(Calendar.HOUR_OF_DAY)+ ":" + c.get(Calendar.MINUTE)+ ":" + c.get(Calendar.SECOND)); }

}

[/CODE]

多谢版主,觉得语言真是难学

没什么，自己多写多看多领悟，我都是自学的。如果你学不会说明你可能还不够努力

第二道题 小应用程序 import java.awt.*; import java.util.*;

public class Watch extends javax.swing.JApplet { private Color butterscotch = new Color(255, 204, 102); private String lastTime = "";

public void init() { setBackground(Color.black); }

public void paint(Graphics screen) { Graphics2D screen2D = (Graphics2D)screen; Font type = new Font("Monospaced", Font.BOLD, 20); screen2D.setFont(type); GregorianCalendar day = new GregorianCalendar(); String time = day.getTime().toString(); screen2D.setColor(Color.black); screen2D.drawString(lastTime, 5, 25); screen2D.setColor(butterscotch); screen2D.drawString(time, 5, 25); try { Thread.sleep(1000); } catch (InterruptedException e) { // do nothing } lastTime = time; repaint(); } }

楼上的设计真是巧妙!!!