我的导出代码：
后台：
Sub toexcel(ByVal ctrl As DataGrid)
HttpContext.Current.Response.AppendHeader("content-disposition", "attachment;filename=excel.xls")
HttpContext.Current.Response.Charset = "UTF-8"
HttpContext.Current.Response.ContentEncoding = System.Text.Encoding.Default
HttpContext.Current.Response.ContentType = "application/ms-excel"
ctrl.Page.EnableViewState = False
Dim tw As New System.IO.StringWriter
Dim hw As New System.Web.UI.HtmlTextWriter(tw)
ctrl.RenderControl(hw)
HttpContext.Current.Response.Write(tw.ToString)
HttpContext.Current.Response.End()
End Sub

Private Sub btn_to_excel_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_to_excel.Click
toexcel(Grid_ygxx_jb)
End Sub
但是运行时点击导出按钮时出错：类型“DataGridLinkButton”的控件“Grid_ygxx_jb__ctl3__ctl1”必须放在具有 runat=server 的窗体标记内。

错在哪里，请高手指点，谢谢！

把这个GGrid_ygxx_jb__ctl3__ctl1放在FORM里面，或者FORM要加“RUNAT=SERVER”

不行啊，没有高手吗？

我也困惑于此啊！！！

在GGrid_ygxx_jb__ctl3__ctl1 里面添加 runat=server

mylover624????

我也这么认为！

哈哈,是啊,我就是 mylover624 啊,MD,我的号被封了(还说我用马甲),没办法,只能用一个新的了啊,