题目是判断某年是否为闰年
#include<stdio.h>
void main()
{
int year,leap;
printf("which year ?");
scanf("%d",^&year);
if(year%400==0) leap=1;
else
if(year%4==0);
if(year%100==0);
else leap=1;
else leap=0;
if(leap==1); ?
printf("%d年是闰年/n",year);
else
printf("%d年不是闰年/n",year);
}

错误的图片如下:

if((n%4==0&&n%100!=0)||(n%400==0))
printf("yes");
else printf("no");

谢谢~我去事实

#include<stdio.h>
void main()
{
int year,leap;
printf("which year ?");
scanf("%d",&year);
if(year%400==0) leap=1;
else
if(year%4==0)
{
if(year%100==0);
else leap=1;
}
else leap=0;
if(leap==1)
printf("%d年是闰年/n",year);
else
printf("%d年不是闰年/n",year);
}

if( (year%4==0&&year%100!=0)||(year%400==0))reaurn 1;
else return0;

楼上的简便！

#include<stdio.h>
void main()
{
int year,leap;
printf("which year ?");
scanf("%d",&year);
if (year%400==0) leap=1;
else
if (year%4==0 || year%100==0)
leap=1;
else leap=0;
if(leap==1)
printf("%d年是闰年/n",year);
else
printf("%d年不是闰年/n",year);
}

#include "stdio.h"

main()
{
int a,leap;
scanf("d%",&a);
if(a%4==0&&a%100==0)
leap=1;
else
leap=0;
if(a%400==0)
leap=1;
else
leap=0;
if(leap==1)
printf("this year is a rui nian");
else
if(leap==0)
printf("this year is not a rui nian");
}

[此贴子已经被作者于2006-5-13 23:43:26编辑过]

楼主的风格好复杂
需要多学一下
c语言算法很重要 是灵魂呀

#include "stdio.h"
main()
{int a;
printf("which year?");
scanf("%d",&a);
(a%4==0&&a%100!=0)||(a%400==0)?printf("yes\n"):printf("no\n");
}