Xin+1= xin + m [ λi (xi+1n – 2xin + xi–1n+1) + b(xi+1n –xi–1n)2/4] 0< i<N
xin+1= xin + 2m [ λi (xi+1n – xin )-h] + bm(h/λi)2 i=0 i=0
xin+1= xin + 2m λi(xi-1n – xin ) i=N
λ= a+bx
h,m,a,b都已知请指教。