通过键盘输入两个整形数分别存放在变量x,y中不借用第三个变量，实现x,y值的互换。（刚学c语言，请问怎么做?)
#include <stdio.h>int main()
{
int x,y;
scanf("%d%d\n",&y,&x);
printf("%d%d\n",x,y);
return 0;
}
上面这个代码哪里错了，我不行了
程序代码：#include <stdio.h>
int main(int argc, char *argv[])
{
int x, y;
long int t;
#define V_DBG
#ifndef V_DBG
/* scanf("%d%d\n", &x, &y); */
#else
x = 1; y = 25;
#endif
//print
printf("org:\t\t\tx = %d, y = %d\n", x, y);
//print->swap
printf("print->swap:\t\tx = %d, y = %d\n", y, x);
//value->swap
t = x; x = y; y = t;
printf("value->swap:\t\tx = %d, y = %d\n", x, y);
//ptr->swap
t = (long int)&x;
((long int *)t)[0] = 0x0000001900000001;
printf("ptr->swap:\t\tx = %d, y = %d\n", x, y);
//arithmetic->swap /* caution: overflow risk */
x += y; y = x - y; x -= y;
printf("arithmetic->swap:\tx = %d, y = %d\n", x, y);
//xor->swap /* caution: overflow risk */
x ^= y; y ^= x; x ^= y;
printf("xor->swap:\t\tx = %d, y = %d\n", x, y);
return 0;
}output sample:
org:x = 1, y = 25
print->swap:x = 25, y = 1
value->swap:x = 25, y = 1
ptr->swap:x = 1, y = 25
arithmetic->swap:x = 25, y = 1
xor->swap:x = 1, y = 25
[此贴子已经被作者于2021-10-31 12:36编辑过]
