编程序实现如下功能：从键盘输入一个包含小数的小写金额（整数部分不超过7位），将其转换为汉字大写金额，最后输出结果。 - C语言论坛

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编程序实现如下功能：从键盘输入一个包含小数的小写金额（整数部分不超过7位），将其转换为汉字大写金额，最后输出结果。

求大佬改正
#include<stdio.h>
main(void)
{
int i,j=0,k,s;
int w[9];
double a,b,c;
scanf("%lf",&a);
a=a+0.001;
s=a;
k=(a-s)*100;
if((a-s)>0)
{
w[1]=k/10;
w[0]=k%10;
}
else
{
w[1]=0;
w[0]=0;
}
while(s!=0)
{
w[2+j]=s%10;
s=s/10;
j++;
}
for(i=9;i>=j+2;i–)
w[i]=0;
for(i=j+1;i>=0;i–)
{
switch(w[i])
{
case 1:printf(“壹”);break;
case 2:printf(“贰”);break;
case 3:printf(“叁”);break;
case 4:printf(“肆”);break;
case 5:printf(“伍”);break;
case 6:printf(“陆”);break;
case 7:printf(“柒”);break;
case 8:printf(“捌”);break;
case 9:printf(“玖”);break;
case 0:printf(“零”);break;
}
switch(i+1)
{
case 1:printf(“分”);break;
case 2:printf(“角”);break;
case 3:printf(“元”);break;
case 4:printf(“拾”);break;
case 5:printf(“佰”);break;
case 6:printf(“仟”);break;
case 7:printf(“万”);break;
case 8:printf(“拾”);break;
case 9:printf(“佰”);break;
}

}
printf("\n");
return 0;
}

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#define _CRT_SECURE_NO_WARNINGS #include<stdio.h> int main(void) { int i, j = 0, k, s; int w[9] = {0}; double a; scanf("%lf", &a); a += 0.001; s = (int)a; k = (a - s) * 100; if ((a - s) > 0) { w[1] = k / 10; w[0] = k % 10; } else { w[1] = 0; w[0] = 0; } while (s != 0) { w[2 + j] = s % 10; s = s / 10; j++; } for (i = j + 1; i >= 0; i--) { switch (w[i]) { case 1:printf("壹"); break; case 2:printf("贰"); break; case 3:printf("叁"); break; case 4:printf("肆"); break; case 5:printf("伍"); break; case 6:printf("陆"); break; case 7:printf("柒"); break; case 8:printf("捌"); break; case 9:printf("玖"); break; case 0:printf("零"); break; } switch (i + 1) { case 1:printf("分"); break; case 2:printf("角"); break; case 3:printf("元"); break; case 4:printf("拾"); break; case 5:printf("佰"); break; case 6:printf("仟"); break; case 7:printf("万"); break; case 8:printf("拾"); break; case 9:printf("佰"); break; } } printf("\n"); return 0; }

#include<stdio.h> int main(void) { int i, n; int w[9] = { 0 }; double a; char d1[] = "零壹贰叁肆伍陆柒捌玖", d2[] = "分角元拾佰仟万拾佰"; scanf("%lf", &a); n = a * 100; for (i = 0; n; n /= 10)w[i++] = n % 10; for (i --; i >= 0; i--) { printf("%c%c%c%c", d1[w[i] * 2], d1[w[i] * 2 + 1],d2[i*2],d2[i*2+1]); } printf("\n"); return 0; }