C ++運算符重載錯誤：使用動態數組時出現雙重釋放或損壞（fasttop）
我是c ++重載運算符的新手，所以可能會有很多語法錯誤。不知道這是什麼問題，在函數聲明或實現中，該如何解決或提出寶貴意見？謝謝
下面的代碼給我一個錯誤：雙重釋放或損壞（fasttop）：
輸入文件
程序代码：6 * 2 2 3 2 3 3 + 2 -5 -5 2 10 10 - 3 9 9 9 3 1 1 1 * 2 2 3 2 3 3 L 2 3 4 N 2 3 4
main.cpp
程序代码：#include <iostream>
#include <fstream>
#include "Vector.h"
using namespace std;
int main()
{
ifstream inFile("input.txt");
if (!inFile)
{
cout << "Read input.txt error" << endl;
exit(1);
}
int testCase;
inFile >> testCase;
while (testCase > 0)
{
char op;
inFile >> op;
Vector v1, v2, v3;
switch (op)
{
case '+':
cout << "v1 + v2" << endl;
inFile >> v1;
inFile >> v2;
cout << "v1:" << v1 << endl;
cout << "v2:" << v2 << endl;
v3 = v1 + v2;
cout << v3 << endl;
break;
case '-':
cout << "v1 - v2" << endl;
inFile >> v1;
inFile >> v2;
cout << "v1:" << v1 << endl;
cout << "v2:" << v2 << endl;
v3 = v1 - v2;
cout << v3 << endl;
break;
case '*':
cout << "v1 * v2" << endl;
inFile >> v1;
inFile >> v2;
cout << "v1:" << v1 << endl;
cout << "v2:" << v2 << endl;
cout << v1 * v2 << endl;
break;
case 'L':
cout << "Length of v1" << endl;
inFile >> v1;
cout << "v1:" << v1 << endl;
cout << v1.length() << endl;
break;
case 'N':
cout << "Normalize of v1" << endl;
inFile >> v1;
cout << "v1:" << v1 << endl;
cout << v1.normalize() << endl;
break;
default:
break;
}
cout << endl;
testCase--;
}
return 0;
}vector.cpp
程序代码：#include "Vector.h"
#include <string>
#include <math.h>
Vector::Vector()
{
currentIndex;
arrSize = 3;
arr = new float[arrSize];
}
Vector::Vector(int size)
{
arrSize = size;
arr = new float[arrSize];
}
Vector::~Vector()
{
delete [] arr;
}
void Vector::AddNumbertoArr(float number)
{
for(int i = 0; i < arrSize; i++)
{
arr[i] = number;
}
}
int Vector::getSize()
{
return arrSize;
}
float Vector::length()
{
float sum=0;
for(int i = 0; i < arrSize; i++)
{
sum+=arr[i]*arr[i];
}
return sqrt(sum);
}
Vector Vector::normalize()
{
float total = length();
for(int i = 0; i < arrSize; i++)
{
arr[i] / total;
}
return Vector(3);
}
Vector & Vector::operator+(Vector v)
{
if(arrSize == v.arrSize)
{
for(int i = 0; i < arrSize; i++)
{
arr[i] += v.arr[i];
}
return *this;
}
else
{
cout << "Error: size not match";
}
}
Vector & Vector::operator=(Vector v)
{
if(arrSize == v.arrSize)
{
for(int i = 0; i < arrSize; i++)
{
arr[i] = v.arr[i];
}
return *this;
}
else
{
cout << "Error: size not match";
}
}
Vector & Vector::operator-(Vector v)
{
if(arrSize == v.arrSize)
{
Vector currentIndex(arrSize);
for(int i = 0; i < arrSize; i++)
{
arr[i] -= v.arr[i];
}
return *this;
}
else
{
cout << "Error: size not match";
}
}
float & Vector::operator*(Vector v)
{
float count;
if(arrSize == v.arrSize)
{
for(int i = 0; i < arrSize; i++)
{
count += this->arr[i] * v.arr[i];
}
return count;
}
else
{
cout << "Error: size not match";
}
}
ifstream & operator>>(ifstream & in, Vector &v)
{
for(int i = 0; i < v.arrSize; i++)
{
in >> v.arr[i];
}
return in;
}
ostream & operator<<(ostream & out, const Vector & v)
{
for(int i = 0; i < v.arrSize; i++)
{
out << v.arr[i];
}
return out;
}Vector.h
程序代码：#pragma once
#include <iostream>
#include <fstream>
using namespace std;
class Vector
{
private:
float *arr;
int currentIndex;
int arrSize;
public:
//constructor
Vector();
Vector(int size);
~Vector();
//setter
void AddNumbertoArr(float number);
//getter
int getSize();
float length();
Vector normalize();
//overload
Vector &operator +(Vector v);
Vector &operator =(Vector v);
Vector &operator -(Vector v);
//dot product
float &operator *(Vector v);
//input output overload
friend ifstream& operator >> (ifstream& in, Vector &v);
friend ostream& operator << (ostream& out, const Vector &v);
};[此贴子已经被作者于2020-5-21 17:31编辑过]
