为小学生输入一个简单算数练习程序，能够完成任意两个10以内的正整数的加减乘除操作，要求能够提示输入答案，能够判断答案是否正确。

#include "stdafx.h"
#include "math.h"
#include"stdlib.h"
#include"time.h"
int main()
{
int i,j,a[10],answer,answer1;
char s;
srand((int)time(0));
for(i=0;i<10;i++)
{
j=1+(int)(10.0*rand()/(RAND_MAX+1.0));
a[i]=j;
}
int choose=1+(int)(4.0*rand()/(RAND_MAX+1.0));
if(choose==1){
s='+';answer=a[4]+a[5];}
else if(choose==2){
s='-';answer=a[4]-a[5];}
else if(choose==3){
s='*';
answer=a[4]*a[5];}
else {s='÷';
answer=a[4]/a[5];}
printf("%d %c %d =   ",a[4],s,a[5]);
scanf("%d",&answer1);
if(answer1==answer)
printf("答案正确");
else printf("答案错误");
return 0;
}

感觉二楼在装 B 我在二楼的基础上改了下，你看看吧

//#include "stdafx.h"
#include <stdio.h>
#include "math.h"
#include"stdlib.h"
#include"time.h"
int main() {
    int i, j, a[10], answer, answer1;
    char s;
    srand((int) time(0));
    for (i = 0; i < 10; i++) {
//        j = 1 + (int) (10.0 * rand() / (RAND_MAX + 1.0));
        j = rand()%10;
        a[i] = j;
    }
    int choose = rand()%3;
    if (choose == 1) {
        s = '+';
        answer = a[4] + a[5];
    } else if (choose == 2) {
        s = '-';
        answer = a[4] - a[5];
    } else if (choose == 3) {
        s = '*';
        answer = a[4] * a[5];
    } else {
        s = '/';
        answer = a[4] / a[5];
    }
    printf("%d %c %d =   ", a[4], s, a[5]);
    scanf("%d", &answer1);
    if (answer1 == answer)
        printf("答案正确");
    else
        printf("答案错误");
    return 0;
}

呵呵，那你是在装什么呢?
写一个牛 B 啊！

二楼只是没有使用代码格式使得版面不好

题目出得泛泛以至于感觉无从下手……就是问问是计算机思维还是数学思维~两个整数相除是要输出什么结果?~