#include<stdio.h>
#include<stdlib.h>
#define len sizeof(struct student)
struct student
{
    long num;
    float score;
    struct student *next;
};

int n;

struct student *creat(void)
{
    struct student *head;
    struct student *p1, *p2;
    n = 0;
    p1 = p2 = (struct student *)malloc(len);
    scanf_s("%ld%f", &p1->num, &p1->score);
    head = NULL;
    while (p1->num != 0)
    {
        n = n + 1;
        if (n == 1)
            head = p1;
        else
            p2->next = p1;
        p2 = p1;
        p1 = (struct student *)malloc(len);
        scanf_s("%ld%f", &p1->num, &p1->score);
    }
    p2->next = NULL;
    return head;
}

void print(struct student *head)
{
    struct student *p;
    printf("\nNow,These %d records are:\n", n);
    p = head;
    if(head!=NULL)
        do
        {
            printf("%ld %5.1f\n", p->num, p->score);
            p->next = p;
        } while (p != NULL);
}

int main()
{
    struct student *creat(void);
    void print(struct student *head);
    struct student *head;
    head = creat();
    print(head);
    return 0;
}

        do
        {
            printf("%ld %5.1f\n", p->num, p->score);
            p= p->next;
        } while (p != NULL);

九九不想说话了~

#include<stdio.h>
#include<stdlib.h>
#define len sizeof(struct student)
struct student
{
    long num;
    float score;
    struct student *next;
};

int n;

struct student *creat(void)
{
    struct student *head;
    struct student *p1, *p2;
    n = 0;
    p1 = (struct student *)malloc(len);
    scanf("%ld%f", &p1->num, &p1->score);
    head = NULL;
    while (p1->num != 0)
    {
        n = n + 1;
        if (n == 1)
            head = p1;
        else
            p2->next = p1;
        p2 = p1;
        p1 = (struct student *)malloc(len);
        scanf("%ld%f", &p1->num, &p1->score);//我编译器用了scanf_s不能编译，改成scanf. 根据自己编译器看着办
    }
    p2->next = NULL;
    return head;
}

void print(struct student *head)
{
    struct student *p;
    printf("\nNow,These %d records are:\n", n);
    p = head;
    if(head!=NULL)
        do
        {
            printf("%ld %5.1f\n", p->num, p->score);
            p = p->next;                //改这里
        } while (p != NULL);
}

int main()
{
    //struct student *creat(void);        //这两句都不要
    //void print(struct student *head);
    struct student *head = creat();
    print(head);
    return 0;
}

为什么这两句都不要？函数呀

此时，要不要写无所谓。
函数调用前需要声明, 前面已经有声明及定义.

大概看一下《编译原理》就知道为什么有时候需要，有时候不需要了。
对于函数使用位于函数实体前的需要函数声明，而函数使用位于函数实体后的可以不需要函数声明。

表示不知道你装了几桶水，我就笑笑

函数声明已在主函数前面完成，主函数只负责调用

我非专业耶！哪有几桶水，顶多半杯水！
刚刚学习了题主的不少帖子，得知题主已经考研了，崇拜ing!!!我也准备今年考哦（只是不会考计算机专业），希望到时得到题主的指导！

[此贴子已经被作者于2017-2-2 11:37编辑过]

typedef struct node {
    char data;
    struct node *next;
    }NODE;

老大，我想问一下，在定义链表类型的时候这也属于递归的吧？定义下一节点指针的时候引用了自己，那么新的节点指针又定义了另一个节点指针，循环往复。内存岂不是很快就占满了？而且没有边界的定义下去，后面的代码为什么可以正确执行呢？应该代码执行到了定义链表这一步就陷入递归的死循环了吧？