#include <stdio.h>
#include <math.h>
int p(int s)
{
    if((int)sqrt((double)s)*(int)sqrt((double)s)==s)
        return 1;
    else return 0;
}
main()
{
/*    int n;
    scanf("%d",&n);
    if(p(n)==1)
        printf("%d",n);
    else
        printf("usb");
}
*/    int a[100];
    int count=0,i;
        while(1){
scanf("%d",&a[i]);

if(p(a[i])==1)
count++;
if(a[i]==0)
break;
        }
        printf("%d",count);
}

#include <math.h>
#include <stdio.h>

int p(int s)
{
    if ((int) sqrt((double) s) * (int) sqrt((double) s) == s) return 1;
    else return 0;
}

int main()
{
    for (int i = 0; i <= 0x10000; ++i)
    {
        int tmp = (int) sqrt((double) i);
        if (!p(i * i)) printf("%d, %d, %d\n", i, tmp, tmp * tmp);
    }
}

你这没按要求来啊，而且 i <= 0x10000;这个语句是什么意思 啊

#include <math.h>
#include <stdio.h>

int p(int s)
{
    if ((int) sqrt((double) s) * (int) sqrt((double) s) == s) return 1;
    else return 0;
}

int main()
{
    int i=0,j=0;
int a[100];
while(scanf("%d",&a[i])&&a[i]!=0){
if(p(a[i])==1)
++j;
}
printf("%d",j);
}

我用这个做就对了

好厉害啊都