#include <stdio.h>
#include <stdlib.h>
#define len 80
int main(){
    char string[len],*pstr;
    int t=0;
   
    pstr=string;
    printf("Input a string:");
    gets(pstr);
      
    while(*pstr++!='\0')
      if(*pstr==' '){
          t++;
          continue;
          printf("%d",t);}
      else
       printf("\n");
     
    if(*pstr=='\0')
      printf("NO space in '%s'.\n,string");
    system("PAUSE");
    return 0;
}
我不知道错在哪，如果可以请帮我指出
题目：用指针方法实现：字符串指针示例：输入一串字符，检测输入的字符串中是否有空格,计算其中空格的个数。

continue会结束本次循环，应把printf放在它前面，后面还有个小问题一并帮你改了

#include <stdio.h>
#include <stdlib.h>
#define len 80
int main(){
    char string[len],*pstr;
    int t=0;
    
    pstr=string;
    printf("Input a string:");
    gets(pstr);
       
    while(*pstr++!='\0')
      if(*pstr==' '){
          t++;
          printf("%d",t);
          continue;
          }
      else
       printf("\n");
     
    if(*pstr=='\0')
      printf("NO space in '%s'.\n",string);
    system("PAUSE");
    return 0;
}

#include <stdio.h>
#include <stdlib.h>
#define len 80
int main()
{
    char string[len];
    char *pstr;
    int t=0;
    printf("Input a string:");
    gets(string);
    pstr = string;

    while(*pstr++!='\0')
    {
         if(*pstr==' ')
         {
              t++;
              continue;
          }
    }

    printf("space is %d",t);

    system("PAUSE");
    return 0;
}