输入今天是x年x月x日,和天数,输出这么多天后是几年级月几日;例如2016 3 9 24000,输出2081 10 5
各位大神,小弟是个C语言新手,求指教:#include <iostream.h>
void main()
{
int a,b,c,n,H,I,m,sum=0,i;
cout<<"please input year month and year and 要增加的天数:";
cin>>a;cin>>b;cin>>c;cin>>n;
H=n%(365*4+1);
I=H/365;
a=a+I+n/(365*4+1)*4;
m=H-(H/365)*365;
if(b=1)m=m+c;
else if(b=2)m=m+31+c;
else if(b=3)m=m+31+28+c;
else if(b=4)m=m+31+28+31+c;
else if(b=5)m=m+31+28+31+30+c;
else if(b=6)m=m+31+28+31+30+31+c;
else if(b=7)m=m+31+28+31+30+31+30+c;
else if(b=8)m=m+31+28+31+30+31+30+31+c;
else if(b=9)m=m+31+28+31+30+31+30+31+31+c;
else if(b=10)m=m+31+28+31+30+31+30+31+31+30+c;
else if(b=11)m=m+31+28+31+30+31+30+31+31+30+31+c;
else if(b=12)m=m+31+28+31+30+31+30+31+31+30+31+30+c;
if(m>365)m=m-365;
else
{
for(i=1;i<=12;i++)
{
if(i<=7&&i%2==1||i>7&&i%2==0)
sum=sum+31;
else if(i==2)sum=sum+28;
else sum=sum+30;
if(sum>=m)
b=b+i;break;
}
}
c=sum-m;
cout<<"year"<<" "<<"mouth"<<" "<<"day"<<" "<<a<<" "<<b<<" "<<c<<endl;
}
输出只有年是对的,大神求助