#include<stdio.h>
#include<iostream>
void main()
{
    int a,b,sum;
    char c;
    printf("please input the two number:");
    scanf_s("%d,%d",&a,&b);
    printf("please input you want the oreap:");
    c=getchar();
    if(c=='+')
    {
        sum=a+b;
        printf("the result=%d",sum);
    }
    if(c=='-')
    {
        sum=a-b;
        printf("the result=%d",sum);
    }
    if(c=='*')
    {
        sum=a*b;
        printf("the result=%d",sum);
    }
    if(c=='/')
    {
        sum=a/b;
        printf("the result=%d",sum);
    }
    system("pause");
}


    这是我的代码，但为什么我到getchar后的代码运行不了，可以详细的说明用getchar来编写四则运算的计算器

还有我是用VS2010编写的

#include<stdio.h>
int main()
{
    int a,b,sum;
    char c;
    printf("please input the two number:");
    scanf("%d,%d",&a,&b);
    while(getchar() != '\n')
        continue;
    printf("please input you want the oreap:");
    scanf("%c",&c);
    while(getchar() != '\n')
        continue;  
    if(c=='+')
    {
        sum=a+b;
        printf("the result=%d",sum);
    }
    if(c=='-')
    {
        sum=a-b;
        printf("the result=%d",sum);
    }
    if(c=='*')
    {
        sum=a*b;
        printf("the result=%d",sum);
    }
    if(c=='/')
    {
        if(a == 0){
            printf("BUG!\n");
            return 0;
        }
        sum=a/b;
        printf("the result=%d",sum);
    }
    return 0;
}

#include <stdio.h>
#include <string.h>

int main( void )
{
    int a, b;
    char opt;

    if( scanf("%d %c%d",&a,&opt,&b)==3 && strchr("+-*/",opt) )
    {
        int result;
        switch( opt )
        {
        case '+': result=a+b; break;
        case '-': result=a-b; break;
        case '*': result=a*b; break;
        case '/': result=a/b; break;
        }
        printf( " = %d\n", result );
    }

    return 0;
}

输入 -3 - +5
输出 = -8
输入 -3--5
输出 = 2