有两队选手，每队出5人进行一对一比赛，甲队为A,B,C,D,E,乙队为
J,K,L,M,N,规定A不和J比赛，M不和D比赛，列出所有可能比赛的名单

#include<iostream>
using namespace std;
class competent
{
public:
    char name;
};
int main()
{
    competent cpt[10];
    short i;
    for(i=65;i<70;i++){cpt[i-65].name=i;cpt[i-60].name=i+9;}
    for(i=0;i<9;i++)
    {
        for(short idx=i+1;idx<10;idx++)
        {
             if((cpt[i].name=='A'&&cpt[idx].name=='J')||(cpt[i].name=='D'&&cpt[idx].name=='M'))
                   ;
             else
             {
                    cout<<cpt[i].name<<" vs. "<<cpt[idx].name<<endl;
              }
        }
    }
    return 0;
}

#include <iostream>

int main( void )
{
    for( unsigned i=0; i!=5*5; ++i )
    {
        char r1 = i/5+'A';
        char r2 = i%5+'J';

        if( (r1=='A' && r2=='J') || (r1=='D' && r2=='M') )
            continue;

        std::cout << r1 << " vs. " << r2 << '\n';
    }
    std::cout << std::flush;

    return 0;
}

额循环加判断...
简单的逻辑题