请看一下，这个程序为什么有问题···（主要是循环不了··） - C语言论坛

第 11 楼

得分:0

回复 6楼我FEI

好的我会试试的！谢谢！

第 12 楼

得分:0

自学中，正好学到结构体这一块。楼主的的printf()语句里面用%s格式输出的地址，实际变量又是char
改写了一下程序如下：

程序代码：

#include <stdio.h>
#define LEN 7

struct SCORE
{
    char * km[LEN];
    float  gpa[LEN];
}first;
int main(void)
{
    int i = 0;
    float e = 0.0;

    first.km[0] = "math";
    first.km[1] = "chinese";
    first.km[2] = "english";
    first.km[3] = "c";
    first.km[4] = "s";
    first.km[5] = "jd";
    first.km[6] ="physical";


    printf("This is the first score in your college\n ");
    printf("please fill in carefully!\n");
    while (i < LEN)
    {
        switch (i)
        {
        case 0 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 1 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 2: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 3: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 4: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 5: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 6: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        }
        i++;
    }
    for (i = 0; i < LEN; i++)
        e += first.gpa[i];
    printf("%.1f\n", e / LEN);

    return 0;
}

人有多懒，编程就有多难。

第 13 楼

得分:0

自学中，正好学到结构体这一块。楼主的的printf()语句里面用%s格式输出的地址，实际变量又是char
改写了一下程序如下：

程序代码：

#include <stdio.h>
#define LEN 7

struct SCORE
{
    char * km[LEN];
    float  gpa[LEN];
}first;
int main(void)
{
    int i = 0;
    float e = 0.0;

    first.km[0] = "math";
    first.km[1] = "chinese";
    first.km[2] = "english";
    first.km[3] = "c";
    first.km[4] = "s";
    first.km[5] = "jd";
    first.km[6] ="physical";


    printf("This is the first score in your college\n ");
    printf("please fill in carefully!\n");
    while (i < LEN)
    {
        switch (i)
        {
        case 0 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 1 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 2: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 3: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 4: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 5: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 6: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        }
        i++;
    }
    for (i = 0; i < LEN; i++)
        e += first.gpa[i];
    printf("%.1f\n", e / LEN);

    return 0;
}

人有多懒，编程就有多难。

第 14 楼

得分:2

自学中，正好学到结构体这一块。楼主的的printf()语句里面用%s格式输出的地址，实际变量又是char
改写了一下程序如下：

程序代码：

#include <stdio.h>
#define LEN 7

struct SCORE
{
    char * km[LEN];
    float  gpa[LEN];
}first;
int main(void)
{
    int i = 0;
    float e = 0.0;

    first.km[0] = "math";
    first.km[1] = "chinese";
    first.km[2] = "english";
    first.km[3] = "c";
    first.km[4] = "s";
    first.km[5] = "jd";
    first.km[6] ="physical";


    printf("This is the first score in your college\n ");
    printf("please fill in carefully!\n");
    while (i < LEN)
    {
        switch (i)
        {
        case 0 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 1 : printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 2: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 3: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 4: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 5: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        case 6: printf("%s: ", first.km[i]);
            scanf("%f", &first.gpa[i]);
            break;
        }
        i++;
    }
    for (i = 0; i < LEN; i++)
        e += first.gpa[i];
    printf("%.1f\n", e / LEN);

    return 0;
}

人有多懒，编程就有多难。

第 15 楼

得分:0

汗，网页刷新问题一下回复了这么多

人有多懒，编程就有多难。