我总觉得大家把简单的问题想复杂了？

一次运行中scanf要接收多行数据，你写的只接收一行

简单啊  你加个循环不就行了？
#include <stdio.h>
int main(int argc, char * argv [ ])
{
    int m,n,s,temp;
    while(scanf("%d%d",&m,&n) != EOF)
    {
        if(m>n)
        {
            temp = m;
            m = n;
            n = temp;
        }
        for(;m <= n;m++)
        {
            temp = m;
            s = 0;
            while(temp)
            {
                s += temp % 10;
                temp = temp / 10;
            }
            if(m%7 == 0 || m%10 ==7 || s%7 ==0)
            {
                printf("%d ",m);
            }
        }
        printf("\n");
    }
    return 0;
}

简单啊  你加个循环不就行了？
#include <stdio.h>
int main(int argc, char * argv [ ])
{
    int m,n,s,temp;
    while(scanf("%d%d",&m,&n) != EOF)
    {
        if(m>n)
        {
            temp = m;
            m = n;
            n = temp;
        }
        for(;m <= n;m++)
        {
            temp = m;
            s = 0;
            while(temp)
            {
                s += temp % 10;
                temp = temp / 10;
            }
            if(m%7 == 0 || m%10 ==7 || s%7 ==0)
            {
                printf("%d ",m);
            }
        }
        printf("\n");
    }
    return 0;
}

我想知道 为啥我回了一贴  却出来了2贴  是bug还是我操作的有问题？

（删除了）还是有点麻烦


[ 本帖最后由 rjsp 于 2015-1-16 16:19 编辑 ]

#include<stdio.h>
int main()
{
    int n,m;//n<m;n<1000,n<1000
    int i,j;
    printf("请输入两个数字n和m\n");
    scanf("%d",&n);
    scanf("%d",&m);
   
    for(i=n;i<=m;i++)
    {
        if(i%7==0||(i%100)%10==7||(i/100+(i%100)/10+i%10)%7==0)// 很关键，第一个是七的整数倍，第二个是个位是七。
            printf("%d\n",i);
        else
        {
            printf("此范围内不存在魔七数\n");
            break;
        }
    }
    return 0;
}