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标题:SQL记录拆分
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jimmy178293
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SQL记录拆分
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请问大家能否把图中两条记录用SQL语句,拆分为4条,也就是查询出来有12条记录,谢谢!
(拆分的依据是S1,S2,S3,S4中有没有数量,有的话独立开来),求救!!!
拆分前:              arrival_id  manual_id    supply_no warehouse_no    goods_no   colorid    long   s1  s2  s3 s4
                      123456      abcd         123a      kkk             fff        ddd         0     0    5   9  0
                      123456      abcd         123a      kkk             zzz        ddd         0     0    4   1  0


这两条记录拆分后如下:arrival_id  manual_id    supply_no warehouse_no    goods_no   colorid    long   s1  s2  s3 s4
                      123456      abcd         123a      kkk             fff        ddd         0     0    5   0  0
                      123456      abcd         123a      kkk             fff        ddd         0     0    0   9  0
                      123456      abcd         123a      kkk             zzz        ddd         0     0    4   0  0
                      123456      abcd         123a      kkk             zzz        ddd         0     0    0   1  0
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2014-12-20 10:43
tlliqi
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先看看
2014-12-21 19:08
jimmy178293
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回复 2楼 tlliqi
大哥求救!
2014-12-22 09:18
volte
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select arrival_id, manual_id,supply_no,,warehouse_no,goods_no,colorid,long,s1, 0 as s2, 0 as s3,0 as s4 from Table where s1>0 and s2=0 and s3=0 and s4=0
union all
select arrival_id, manual_id,supply_no,,warehouse_no,goods_no,colorid,long,0 as s1, s2, 0 as s3,0 as s4 from Table where s1=0 and s2>0 and s3=0 and s4=0
union all
select arrival_id, manual_id,supply_no,,warehouse_no,goods_no,colorid,long,0 as s1, 0 as s2, s3,0 as s4 from Table where s1=0 and s2=0 and s3>0 and s4=0
union all
select arrival_id, manual_id,supply_no,,warehouse_no,goods_no,colorid,long,0 as s1, 0 as s2, 0 as s3,s4 from Table where s1=0 and s2=0 and s3=0 and s4>0


大家都是朋友,有空就来坐坐!
2014-12-24 13:07
antjl
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---个人习惯,首字母大写,便于阅读;
---算法:
---     1、S1列到S4列不管有没有0都要求结果有是0的行;
---     2、S1列到S4如果非0的话,单独列一行;
---     3、Union会自动剔除重复行
Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],0 As S1,S2,S3,S4 From Arrival
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,0 As S2,S3,S4 From Arrival
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,0 As S3,S4 From Arrival
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,S3,0 As S4 From Arrival
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,S3,S4 From Arrival Where S1<>0
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,S3,S4 From Arrival Where S2<>0
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,S3,S4 From Arrival Where S3<>0
Union Select Arrival_ID,Manual_ID,Supply_No,Warehouse_No,Goods_No,ColorID,[Long],S1,S2,S3,S4 From Arrival Where S4<>0
2014-12-26 16:57
快速回复:SQL记录拆分
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