#include"stdio.h"
      main()
      {
        int i,s,j=0,dnum=26;
        char a[100];
            for(i=0;dnum>0;i++)
         {
              s=dnum%16;
             if(s>=0&&s<=9)
             {
                a[i]='0'+s;
             }
             else
            {
              a[i]=s-10+'a';
             }
             dnum/=16;
             j++;
          }


             for(i=j-1;dnum>0;i--)
             printf("%c",a[i]);

          getch();
      }

   #include"stdio.h"
   void  transformToHex(int dnum,char *hex);

main()
{
 int i,t;
 char a[100];
  scanf("%d",&t);
 transformToHex(t,a);
 for(i=strlen(a)-1;t>0;i--)
 printf("%c",a[i]);

}
void  transformToHex(int dnum,char *hex)
{

  int t,i=0;
while(dnum)
{
t=dnum%16;
if(t>=0&&t<=9)
{
*(hex+i)=t+'0';
i++;
}
else
{
*(hex+i)=t-10+'a';
i++;
}
dnum/=16;

}
*(hex+strlen(hex)-1)='\0';



}

各位大哥，看一看啊

试一下这个看
#include<stdio.h>
int main()
{
        int i = 0, j, m;
        char a[10] = "0", b[16] = "0123456789abcdef";
        printf("please input a number\n");
        scanf("%d", &m);
        while(m != 0)
        {
                j = m % 16;
                a[i++] = b[j];
                m = m / 16;
        }
        for(; i >= 0; i--)
                printf("%c", a[i]);
        printf("\n");
        return 0;
}

看不懂！

看看2楼的代码，哪错啦，谢谢！

void TranTo16(unsigned long a)
{
    unsigned long b;
    int i;
    char c[]="0123456789abcdef";
    for(i=0;i<32;i+=4)
    {
        b=a<<i;
        printf("%c",c[b>>28]);
    }
    printf("\n");
}

#include<stdio.h>
int main(void)
{
   int x;
   scanf("%d",&x);//十进制的符号就是%d
   printf("%x",x);//十六进制的符号就是%x
   return 0;
}
这个多简单呀，为什么要写那么复杂的呀

8楼的代码，输入多组数据结果怎么不对了呀