请高手速回，务必正确程序。

#include <stdio.h>
#include <math.h>

main()
{
       double x1,x2;
       x1=(6+sqrt(6*6+4))/2;
       x2=(6-sqrt(6*6+4))/2;
       while(-10<x1<10)
       {
                       printf("%f\n",x1);
                       break;
                       }
                       while(-10<x2<10)
                       {
                                       printf("%f\n",x2);
                                       break;
                                       }
   
      system("pause");
}

#include<stdio.h>
#include<math.h>
int main()
{
    float a,b,c,temp;
    float x1,x2;
    printf("ax^2+bx+c=0的根，输入a,b,c:");
    scanf("%f,%f,%f",&a,&b,&c);
    temp=sqrt(b*b-4*a*c);
    if(temp<0)
    {
        printf("没有实根");
    }
    else if(temp==0)
    {
      x1=(-b)/(2*a);
      printf("存在一个实根为%f",x1);
    }
    else
    {
      x1=((-b)+temp)/(2*a);
      x2=((-b)-temp)/(2*a);
      printf("存在两个实根%f,%f",x1,x2);
    }
    return 0;
}

用对分法,OK??