把结构数组 传递给函数

#include<stdio.h>
void  vvv(struct persons *p);
struct names {

 char firstname[20];

 char middlename[20];

 char lastname[20];
};

struct persons{

 int number;

 struct names name;
};
  struct persons person[5] = {
  {302039823,{"Dribble","Mackede","Flossie"}},
  {345345345,{"gadenfs","Kasdfas","Pszajkh"}},
  {302039823,{"Kazsdfj","Aasdfaf","Mjasdfh"}},
  {302039823,{"Qaadsef","ddghfhtty","Yjsjdsh"}},
  {302039823,{"Bsdsdfs","Fsjdsdd","Rshdsdf"}}
   };

int main(void)
{
    vvv(person);
   return 0;
}
void  vvv(struct persons *p)
{
   int i;
   for(i=0;i<5;i++)
    printf("%s, %s %c. -- %d\n",p[i].name.firstname, p[i].name.lastname, p[i].name.middlename[0], p[i].number);

}

弱弱的问下哪里出错了

1、把vvv的函数声明放在persons结构的定义之后。

2、或者在vvv函数的声明之前先声明persons结构（在void  vvv(struct persons *p);之前加一句struct persons;）。