多谢大神的回复 感激不尽
但是你这个程序是适用于我给出的那五个数字呀 如果这个五个数字是1-9之间random的呢
我写的那两组就是举个例子～

额。。。这个只用于这个2诶 我给的数组就是举个例子～
如果是输入1-9之间任意的五个数呢？

我找到方法拉～ 感谢版主的提点！！！我实在太迟钝嘞。。。。

t版好有爱

luguo

我那个也只是例子，你用任何方法给出那个data数组就可以了，元素数量任意，不限于5个，代码都不用变。

//A program which does the scoring for game CSEzee
//CSEzee is played by rolling five 9-sided(1-9) dice.
//The program will give the score of the input by following CSEzee rules.
//
//20/04/2013

#include <stdio.h>
#define N_DICE 5
#define NUMBER 9


int main(void) {
    int x[N_DICE],number_table[9] = {0};
    int n[NUMBER]={1,2,3,4,5,6,7,8,9};
    int i,j, score = 0, score2 = 0;
    
    //storage of five input
    i = 0;
    for (i = 0;i < N_DICE; i++) {
        scanf("%d", &x[i]);
    }
    for (i = 0;i < N_DICE; i++) {
        //5 interger from 1 to five must be supplied
        if (1 <= x[i]&&x[i] <=9) {
            //sum of any throw
            for (i = 0;i < N_DICE;i++) {
                score = score + x[i];
            }
            //the number_table is used to memorize the number
            //of times of the appearance of interger 1..9
            for (i = 0;i < N_DICE;i++) {
                for (j = 0;j < NUMBER;j++) {
                    if (x[i]==n[j])
                        number_table[j] = number_table[j] + 1;
                }
            }
            for (j = 0;j < NUMBER;j++) {
                if (number_table[j] == 2) {
                    score2 = 14 + 2 * n[j];
                }else if (number_table[j] == 3) {
                    score2 = 15 + 3 * n[j];
                }else if (number_table[j] == 4) {
                    score2 = 16 + 4 * n[j];
                }else if (number_table[j] == 5) {
                    score2 = 17 + 5 * n[j];
                }
            }
            //the hihgest score will be printed
            for (j = 0;j < NUMBER;j++) {
                if (score > score2) {
                    printf("CSEzee score is %d: sum.\n",score);
                }else if (number_table[j] == 2) {
                    printf("CSEzee score is %d: pair of %d's\n",score2,n[j]);
                }else if (number_table[j] == 3) {
                    printf("CSEzee score is %d: three %d's\n",score2,n[j]);
                }else if (number_table[j] == 4) {
                    printf("CSEzee score is %d: four %d's\n",score2,n[j]);
                }else if (number_table[j] == 5) {
                    printf("CSEzee score is %d: five %d's\n",score2,n[j]);
                }
            }
            
        }else{
            printf("Invalid input: 5 integers 1..9 must be supplied.\n");
        }
    }
    return 0;
}

刚刚收到静夜思的私信说要我po出来解决办法～
但是我这个有个问题就是 如果只是sum的话 输出的sum就会重复9遍 如图

我也知道是怎样造成的 因为比了九次循环了九次所以就print了九次 但我不知道怎么改。。。

求教大神 求教版主～～

少见啊！MM还是面子大

luoguo