一个简单的题目台州acm的
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#include<stdio.h> int main() { int n,m,x1,y1; float x2,y2; while(scanf("%d%d",&n,&m)&&(n!=0&&m!=0)) { if(m>2*n&&m<4*n) { x1=2*n-m/2; x2=2.0*n-m/2.0; y1=m/2-n; y2=m/2.0-n; if((x2-x1)&&(y2-y1)) printf("%d %d",x,y); else printf("Error"); } else printf("Error"); } return 0; }自己写的代码
题目是这个链接http://acm.tzc.
开始做acm题目,新手只能做做简单的