求解密高手，大家都进来看看
fcl_admin`--
CREATE TABLE IF NOT EXISTS `fcl_admin` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`adminName` varchar(50) DEFAULT NULL,
`adminPass` varchar(50) DEFAULT NULL,
`adminRank` int(11) DEFAULT NULL,
`adminIp` varchar(50) DEFAULT NULL,
`ipcheck` tinyint(4) DEFAULT NULL,
`ip` varchar(255) DEFAULT NULL,
`maccheck` tinyint(4) DEFAULT NULL,
`mac` varchar(255) DEFAULT NULL,
`hdecheck` tinyint(4) DEFAULT NULL,
`hde` varchar(255) DEFAULT NULL,
`cpucheck` tinyint(4) DEFAULT NULL,
`cpu` varchar(255) DEFAULT NULL,
`aid` int(11) DEFAULT '0',
`mobilecheck` tinyint(4) DEFAULT NULL,
`mobile` varchar(255) DEFAULT NULL,
`mibaokacheck` tinyint(4) DEFAULT NULL,
`mibaoka` varchar(255) DEFAULT NULL,
`rights` text,
PRIMARY KEY (`id`),
KEY `id` (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=12 ;
INSERT INTO `fcl_admin` (`id`, `adminName`, `adminPass`, `adminRank`, `adminIp`, `ipcheck`, `ip`, `maccheck`, `mac`, `hdecheck`, `hde`, `cpucheck`, `cpu`, `aid`, `mobilecheck`, `mobile`, `mibaokacheck`, `mibaoka`, `rights`) VALUES
(11, 'admin', '21232f297a57a5a743894a0e4a801fc3', 1, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 0, NULL, NULL, NULL, NULL, '1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0');
adminPass 的值：21232f297a57a5a743894a0e4a801fc3 是MD5 32位加密 已破解
求解密：rights 的值：1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
这是神马加密？
求原字符 和 这种类型加密方法
