#include <stdio.h>

int main(void)
{
    int i, j, max, maxi, maxj, m, n, a[20][20], flag;

    printf("Please input m and n:");
    scanf("%d%d", &m, &n);
    printf("Please input a juZhen(%d hang, %d lie):\n", m, n);
    for(i=0; i<m; i++)
    {
        for(j=0; j<n; j++)
        {
            scanf("%d", &a[i][j]);
        }
    }
    for(i=0; i<m; i++)
    {
        max = a[i][0];
        for(j=1; j<m; j++)
        {
            if(max<a[i][j])
            max = a[i][j];
            maxi = i;
            maxj = j;
        }
        
        for(i=0; i<m; i++)
        {
            if(max>a[i][maxj])
            {
                flag = 0;
                break;
            }
            else
            {
                flag = 1;
                continue;
            }
        }
        if(flag == 1)
        {
            printf("\nyou an dian, wei: juZhen[%d][%d]=%d\n", m, n, max);
            break;
        }
    }
    if(flag==0)
    {
        printf("\nmei you an dian.\n");
    }

    return 0;
}



自己的想法   但是不能运行   是个死程序    求大神指教鞍点意为本行中最大元素与该列最小元素是同一个数

[ 本帖最后由 a576008304 于 2012-11-22 12:26 编辑 ]

我也是新人 帮顶了

还是谢谢！！！

惊奇的发现    其他简单的数组都能运行且结果正确   复杂点的机数大一点的就不能运行。。。。。。。   

#include <stdio.h>

int main(void)
{
    int i, j, max, maxi, maxj, m, n, a[20][20], flag;

    printf("Please input m and n:");
    scanf("%d%d", &m, &n);
    printf("Please input a juZhen(%d hang, %d lie):\n", m, n);
    for(i=0; i<m; i++)
    {
        for(j=0; j<n; j++)
        {
            scanf("%d", &a[i][j]);
        }
    }
    for(i=0; i<m; i++)
    {
        max = a[i][0];
        for(j=1; j<m; j++)//这里的m应为n吧
        {
            if(max<a[i][j])
            max = a[i][j];
            maxi = i;
            maxj = j;
        }
       
        for(i=0; i<m; i++) //这里的m应为n吧 并且在这里给i重新赋值会破坏外循环中的i值，
        {
            if(max>a[i][maxj])
            {
                flag = 0;
                break;
            }
            else
            {
                flag = 1;
                continue;
            }
        }
        if(flag == 1)
        {
            printf("\nyou an dian, wei: juZhen[%d][%d]=%d\n", m, n, max);
            break;
        }
    }
    if(flag==0)
    {
        printf("\nmei you an dian.\n");
    }

    return 0;
}

正确结果：
#include <stdio.h>

int main(void)
{
    int i, j, max, maxi, maxj, m, n, a[20][20], flag, k;

    printf("Please input m and n:");
    scanf("%d%d", &m, &n);
    printf("Please input a juZhen(%d hang, %d lie):\n", m, n);
    for(i=0; i<m; i++)
    {
        for(j=0; j<n; j++)
        {
            scanf("%d", &a[i][j]);
        }
    }
    for(i=0; i<m; i++)
    {
        max = a[i][0];
        for(j=1; j<n; j++)//多谢楼上大哥提醒
        {
            if(max<a[i][j])
            {
                max = a[i][j];
                maxi = i;
                maxj = j;
            }
            else     /一开始没有加这一部分，本行最大值若不是在最后求不出来，这是什么问题。。。if后面若没有else程序是怎样运行的？
            {
                continue;
            }       /
        }
        
        for(k=0; k<m; k++)//多谢楼上大哥提醒，这里再给i复制就破坏了外层的i值
        {
            if(max>a[k][maxj])
            {
                flag = 0;
                break;
            }
            else
            {
                flag = 1;
                continue;
            }
        }
        if(flag == 1)
        {
            printf("\nyou an dian, wei: juZhen[%d][%d]=%d\n", maxi, maxj, max);
            break;
        }

    }
    if(flag==0)
    {
        printf("\nmei you an dian.\n");
    }

    return 0;
}


正确结果