如下程序: (MSDN的fflush函数的例子)
    #include <stdio.h>
   
    void main( void )
        {
        int integer;
        char string[81];
        
        /* Read each word as a string. */
        printf( "Enter a sentence of four words with scanf: " );
        for( integer = 0; integer < 4; integer++ )
        {
            scanf( "%s", string );
            printf( "%s\n", string );
        }
        
        /* You must flush the input buffer before using gets. */
        fflush( stdin );
        printf( "Enter the same sentence with gets: " );
        gets( string );
        printf( "%s\n", string );
    }
   
    上述程序在Windows下运行得到预期结果:
    Enter a sentence of four words with scanf: This is a test(回车)
        This
        is
        a
        test
        Enter the same sentence with gets: This is a test(回车)
        This is a test
   
    但是在Linux(Ubuntu 12)下第一个回车后程序正确输出4个单词,但然后显示"Enter the same sentence with gets:" 后便直接退出:
   
    Enter a sentence of four words with scanf: This is a test
        This
        is
        a
        test
        Enter the sane sentence with gets:
        ubuntu@ubuntu-VM:~/Desktop/workspace/strean$
        
        谁能告诉我,为什么Linux下的fflush不起作用呢?

fflush( stdin );

这个东西本来是用于输出的 所以linux下不好使 windows下扩展了这个函数的用法 所以可以用于stdin

因此 linux下不能用

至于这个扩展好不好呢 见仁见智 不知道各位大牛怎么看

那如何才能实现刷新输入缓冲呢?

谷歌一下你就知道

http://

多谢