怎么用C编写{（x,y,z）满足方程：x^2+y^2+z^2=55^2(注：要求 x > y > z),则（x,y,z）称为方程的一个解。试求方程的整数解（包括负整数解）的个数。}

x=-19,y=-30,z=-42
x=-18,y=-26,z=-45
x=-10,y=-30,z=-45
x=-10,y=-18,z=-51
x=-6,y=-35,z=-42
x=-3,y=-30,z=-46
x=-3,y=-10,z=-54
x=0,y=-33,z=-44
x=3,y=-30,z=-46
x=3,y=-10,z=-54
x=6,y=-35,z=-42
x=10,y=-30,z=-45
x=10,y=-18,z=-51
x=10,y=-3,z=-54
x=10,y=3,z=-54
x=18,y=-26,z=-45
x=18,y=-10,z=-51
x=18,y=10,z=-51
x=19,y=-30,z=-42
x=26,y=-18,z=-45
x=26,y=18,z=-45
x=30,y=-30,z=-35
x=30,y=-19,z=-42
x=30,y=-10,z=-45
x=30,y=-3,z=-46
x=30,y=3,z=-46
x=30,y=10,z=-45
x=30,y=19,z=-42
x=33,y=0,z=-44
x=35,y=-6,z=-42
x=35,y=6,z=-42
x=35,y=30,z=-30
x=42,y=-19,z=-30
x=42,y=-6,z=-35
x=42,y=6,z=-35
x=42,y=19,z=-30
x=42,y=30,z=-19
x=42,y=30,z=19
x=42,y=35,z=-6
x=42,y=35,z=6
x=44,y=0,z=-33
x=44,y=33,z=0
x=45,y=-18,z=-26
x=45,y=-10,z=-30
x=45,y=10,z=-30
x=45,y=18,z=-26
x=45,y=26,z=-18
x=45,y=26,z=18
x=45,y=30,z=-10
x=45,y=30,z=10
x=46,y=-3,z=-30
x=46,y=3,z=-30
x=46,y=30,z=-3
x=46,y=30,z=3
x=51,y=-10,z=-18
x=51,y=10,z=-18
x=51,y=18,z=-10
x=51,y=18,z=10
x=54,y=-3,z=-10
x=54,y=3,z=-10
x=54,y=10,z=-3
x=54,y=10,z=3

int _tmain(int argc, _TCHAR* argv[])
{
    int x=-55, y=-55, z=-55;
    int num = 0;

    while (x++ < 56)
    {
        y = -55;
        while (y++ < 56)
        {
            z = -55;
            while (z++ < 56)
            {
                if ((x>y)&&(y>z)&&(55*55==x*x+y*y+z*z))
                {
                    printf("x=%d,y=%d,z=%d\n",x,y,z);
                    num++;
                }
            }
        }
    }

    printf("\n共有%d个",num);
    return 0;

}

不知道对不对

#include <stdio.h>

int main(int argc, char* argv[])
{
    int x,y,z,count=0;
    for(x=-55;x<55;x++)
        for(y=-55;y<x;y++)
            for(z=-55;z<y;z++)
                if(x*x+y*y+z*z==55*55)
                {
                    printf("x=%d,y=%d,z=%d\n",x,y,z);
                    count++;
                }
    printf("The total number is %d\n",count);
    return 0;
}

共有62个