宏定义中printf中的‘#’
先看一例：#include<iostream>
#include<cstdio>
using namespace std;
#define print(x) printf("the No. "#x", is ")
int main()
{
print(10);//输出：the No. 10, is
print("abc");//输出：the No. "abc", is
print(abc);//输出：the No. abc, is
int y=10;
printf("#y");//输出：#y
cout<<endl;
return 0;
}
请问printf中的#在宏定义中起什么作用啊？
