我用Datagridview 现实ACCESS表中的内容。
数据库连接如下：
 public class db
    {
        public db()
        {
            //
            // TODO: 在此处添加构造函数逻辑
            //
        }
        public static string connection
        {
            get
            {return"Data Source=123.mdb;Jet OLEDB:Engine Type=5;Provider=Microsoft.Jet.OLEDB.4.0;";}
        }
    }
显示程序如下：
public partial class Form1 : Form
    {
        private OleDbConnection oleConnection1 = null;
        public Form1()
        {
            InitializeComponent();
            this.oleConnection1 = new OleDbConnection(datagrid.database.db.connection);
        }
        DataSet ds;
        private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
        {
            oleConnection1.Open();
            string sql = "select A as 姓名,B as 密码 from ss";
            OleDbDataAdapter adp = new OleDbDataAdapter(sql, oleConnection1);
            ds = new DataSet();
            ds.Clear();
            adp.Fill(ds, "ss");
            dataGridView1.DataSource = ds.Tables["Tss"].DefaultView;
            //dataGrid1.CaptionText = "共有" + ds.Tables["person"].Rows.Count + "条记录";
            oleConnection1.Close();
        }
      
    }

但是就是显示不出来，也没报错。本人初学，请大神帮忙啊！！

dataGridView1.DataSource = ds.Tables["Tss"].DefaultView;
[]里面用"ss"吧

改过了也不可以

dataGridView的属性没设置

怎么设置？本人编程白痴，敬请指导啊，谢谢啊

  adp.Fill(ds, "ss");
  dataGridView1.DataSource = ds.Tables["Tss"].DefaultView;
将上面，两句话，改为
adp.Fill(ds);
  dataGridView1.DataSource = ds.Tables[0].DefaultView;即可