string hexOutput = "";
                char[] values = txtRcv.Text.ToCharArray();
                foreach (char letter in values)
                {
                    int value = Convert.ToInt32(letter);
                    hexOutput += String.Format("{0:X}", value);
                }
                txtRcv.Text = hexOutput;
我的这段代码已经可以将11转化为16进制的31 31了，我要解决的就是取消点选将十六进制的31 31 转化为11，请帮忙指教，我是这样写的，但是不对
                string strOutput = "";
                char[] values = txtSend.Text.ToCharArray();
                foreach (char letter in values)
                {
                    int value = Convert.ToInt32(letter);
                    byte[] data = System.BitConverter.GetBytes(value);
                    strOutput += Encoding.ASCII.GetString(data);
                }
                txtSend.Text = strOutput;

分数我会给你的