程序代码：

int c, k;
double res = 0, xp = 1.0;

for (c=1, k=0; k < m; k++) {
    res += c * xp;
    c *= (m-k)/(k+1);
    xp *= x;
}

程序代码：

#include<iostream>

#include<cmath>
using namespace std;
int main() {
    double x,sum=0;
    int m;
    cout<<"please give m,x:"<<endl;
    cin>>m;
    cin>>x;
    int a=1;
    sum+=a;
    for(int i=1;i<m+1;i++) {
        a=a*(m-i+1)/i;
        sum+=a*pow(x,i);
    }
    cout<<"(1+x)^m= "<<sum<<endl;
    cout<<"(1+x)^m= "<<pow(1+x,m)<<endl;
    return 0;
}