如题
如输入的是00000000000000000000000001001
输出为：  10010000000000000000000000000

[ 本帖最后由 路在前方 于 2010-11-18 10:18 编辑 ]

利用数组和指针就可以了吧？
要再深入了解你的题目要求

呵呵 外面不是有个帖子 用union标识出byte的bits么
你可以用 bswap 先逆转byte位 然后再逆转单byte的bits

直接进行按位异或试试。

心情郁闷，上论坛混混日子，写来耍耍吧。：）

#include <stdio.h>

int main(void){
    unsigned long  flag[32] = {0x1,0x2,0x4,0x8,
                               0x10,0x20,0x40,0x80,
                               0x100,0x200,0x400,0x800,
                               0x1000,0x2000,0x4000,0x8000,
                               0x10000,0x20000,0x40000,0x80000,
                               0x100000,0x200000,0x400000,0x800000,
                               0x1000000,0x2000000,0x4000000,0x8000000,
                               0x10000000,0x20000000,0x40000000,0x80000000};
    int i;
    unsigned long  x;
    unsigned long  temp1;
    unsigned long  temp2;
   
    printf("请输入一个整数(十进制)：");
    scanf("%ld", &x);
   
    for(i = 0; i < 16; i++){
        temp1 = x & flag[i];
        temp2 = x & flag[31 - i];
        if(temp1 == flag[i]){
                 if(temp2 != flag[31 -i]){
                          x = x^flag[i];
                          x = x|flag[31 - i];              
                 }
        }
        else{
             if(temp2 == flag[31 -i]){
                     x = x|flag[i];
                     x = x^flag[31 - i];
             }
        }
    }

    printf("DWORD倒置的结果为：%ld", x);

    return 0;
}