麻烦问一下这个问题在loop上出不了结果
题目大意是：有一个忍者和海盗对打，两人中间隔着一定距离且中间放着一把刀。忍者可以迅速跑到刀那里并捡起防御海盗的攻击。海盗有一把枪，需要做上膛耗费一定时间。如果海盗上完膛，忍着没拿到刀，则海盗胜。反之可推。
初步我写的pseudo-code
float ninjaSpeed,pirateTime, combatDistance, swordDistance

  print "Please enter a speed for the ninja: "
  ninjaSpeed <- readInput

  print "Please enter a draw and shoot time for the pirate: "
  pirateTime <- readInput

  print "Please enter a combat distance: "
  combatDistance <- readInput

  print "Please enter the distance to the sword: "
  swordDistance <- readInput

  if (swordDistance / ninjaSpeed <=pirateTime)
     print "The ninja makes it to his sword. Yay for the ninja!" endline
  else
     print "The pirate shoots the ninja dead. Yay for teh pirate!" endline

然后就是这道题目的给出的例子了（应当像这样运行）：
Please enter the distance between the ninja and the pirate (in meters): 100
How far away is the ninja from his sword (in meters): 20
Please enter the ninja's running speed (meters per second): 9
Please enter the number of seconds it takes the pirate to draw and fire his gun: 3

The ninja starts 20 meters from the sword
The pirate takes 3 seconds to draw and fire his gun.
A
fter 1 second the ninja is 11 meters from the sword and the pirate will draw and fire his gun in 2 seconds.
After 2 seconds the ninja is 2 meters from the sword and the pirate will draw and fire his gun in 1 second.
The ninja makes it to his sword before getting shot.
这是我写的部分
#include <iostream>

using namespace std;

int main()
{
  int ninjaSpeed, pirateTime, combatDistance, swordDistance ,time = 0;

 
  cout<<"Please enter the distance between the ninja and the pirate (in meters):";
  cin>>combatDistance;
  cout<<"How far away is the ninja from his sword (in meters):";
  cin>>swordDistance;
  cout<<"Please enter the ninja's running speed (meters per second):" ;
  cin>>ninjaSpeed;
  cout<<"Please enter the number of seconds it takes the pirate to draw and fire his gun:" ;
  cin>>pirateTime;
 
  do
   {
     swordDistance = swordDistance - (ninjaSpeed*time);
      pirateTime = pirateTime - time;
      time=time+1;
 
    }
      while (NswordDistance / ninjaSpeed >=pirateTime);

       cout<<"After"<< time << "second the ninja is "<< NswordDistance << "meters from the sword and the pirate will draw and fire his gun in " << NpirateTime<<" seconds"<<endl;
 
  return 0;
}

我loop这里还是不太懂，既然是do-while loop 那么这样写应该会出现例子中给的结果，但我运行的时候却出不来，还请各位多多指点。



























[ 本帖最后由 razielzyc 于 2010-10-13 11:51 编辑 ]

给你修改了一下，加了一些注释，能得到你的结果，但是你的原理上有bug,eg:pirateTime=3时恰好swordDistance变为0，算谁win.
#include <iostream>

using namespace std;

int main()
{
  int ninjaSpeed, pirateTime, combatDistance, swordDistance ,time = 1;//ninjia武士，pirate海盗，combat战斗，sword刀，time的初值修改为1


  cout<<"Please enter the distance between the ninja and the pirate (in meters):";
  cin>>combatDistance;
  cout<<"How far away is the ninja from his sword (in meters):";
  cin>>swordDistance;
  cout<<"Please enter the ninja's running speed (meters per second):" ;
  cin>>ninjaSpeed;
  cout<<"Please enter the number of seconds it takes the pirate to draw and fire his gun:" ;
  cin>>pirateTime;

  do
   {
     swordDistance = swordDistance - ninjaSpeed;// swordDistance 是变化后的值，无须*上time
      pirateTime = pirateTime - 1;// pirateTime每次递减1
      if(swordDistance<0)
      {
          cout<<"The ninja makes it to his sword before getting shot.";
          break;
      }

      cout<<"After"<< time << "second the ninja is "<< swordDistance << "meters from the sword and the pirate will draw and fire his gun in " << pirateTime<<" seconds"<<endl;//加在loop里面
      time=time+1;

    }while (pirateTime>0);//swordDistance值已修改