请专家改下程序(使之符合要求)
C语言程序设计－－心算抢答系统#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void main()
{int simple();
int mix();
void exchange(int *p1,int *p2,int *p3);
struct team
{char name;
int score;
}tea[3]={{'A',100},{'B',100},{'C',100}};
int i,p,j,t,k,n,m;
int a,b,c;
int result1,answer1,result2,answer2;
int *q1,*q2,*q3;
char ch1,ch2;
printf(" ************************************\n");
printf(" $ $\n");
printf(" $ $\n");
printf(" $ welcome jion in this competition!$\n");
printf(" $ $\n");
printf(" $ $\n");
printf(" ************************************\n");
for(i=0;i<10;i++)
printf("\n");
printf("input simple count number n:");
scanf("%d",&n);
printf("\ninput mix count number m:");
scanf("%d",&m);
printf("\n");
printf(" press any key to begain ! \n");
getch();
printf("Begain!\n");
printf("The first turn.\n");
printf("This is simple count.\n");
printf("Please look at the question:\n");
for(p=0;p<n;p++)
{result1=simple();
printf("Please input one team name:");
getchar();
scanf("%c",&ch1);
printf("\ninput your answer:");
scanf("%d",&answer1);
for(k=0;k<3;k++)
{t=k;
if(ch1==tea[k].name)
if(result1==answer1)
tea[t].score+=5;
else
{ printf("This answer is wrong.\n");
printf("The right answer is %d\n",result1);
tea[t].score-=5;
}
}
for(i=0;i<3;i++)
printf("%c%d\n",tea[i].name,tea[i].score);
}
printf("This turn is end.\n");
printf("\n\n\n\n\n");
printf("The second turn begain!\n");
printf("This is mix count!\n");
printf("Please look at the question:\n");
for(j=0;j<m;j++)
{result2=mix();
printf("please input one team:");
getchar();
scanf("%c",&ch2);
printf("\ninput your answer:");
scanf("%d",&answer2);
for(i=0;i<3;i++)
{t=i;
if(ch2==tea[i].name)
if(result2==answer2)
tea[t].score+=10;
else
{ printf("\nyour answer is wrong.\n");
printf("The right answer is %d\n",result2);
tea[t].score-=10;
}
}
for(i=0;i<3;i++)
printf("%c%d\n",tea[i].name,tea[i].score);
}
a=tea[0].score;b=tea[1].score;c=tea[2].score;
if(a>b&&b>c)
printf("%c %c %c\n",'A','B','C');
if(a>b&&c>a)
printf("%c %c %c",'C','A','B');
if(a>b&&a>c&&c>b)
printf("%c %c %c\n",'A','C','B');
if(c>a&&c>b&&b>a)
printf("%c %c %c\n",'C','B','A');
if(b>a&&c>a&&b>c)
printf("%c %c %c\n",'B','C','A');
if(b>a&&a>c)
printf("%c %c %c\n",'B','A','C');
q1=&tea[0].score;
q2=&tea[1].score;
q3=&tea[2].score;
exchange(q1,q2,q3);
printf("%d %d %d\n",tea[0].score,tea[1].score,tea[2].score);
}
simple()
{int s,num1,num2,stpy;
srand((unsigned)time(NULL));
num1=rand()%100+1;
num2=rand()%100+1;
stpy=rand()%4+1;
switch(stpy)
{case 1:s=num1+num2;
printf("%d+%d=?\n",num1,num2);break;
case 2:if(num1>=num2)
{ s=num1-num2;
printf("%d-%d=?\n",num1,num2);break;
}
else
{ s=num2-num1;
printf("%d-%d=?\n",num2,num1);break;
}
case 3:s=num1*num2;
printf("%d*%d=?\n",num1,num2);break;
case 4:s=num1/num2;
printf("%d/%d=?\n",num1,num2);break;
}
return(s);
}
mix()
{int t,num1,num2,num3,stpy;
srand((unsigned)time(NULL));
num1=rand()%9+1;
num2=rand()%9+1;
num3=rand()%9+1;
stpy=rand()%4+1;
switch(stpy)
{case 1:t=(num1+num2)*(num2-num3);
printf("(%d+%d)*(%d-%d)=?\n",num1,num2,num2,num3);
break;
case 2:t=num1*num2/num3;
printf("%d*%d/%d=?\n",num1,num2,num3);
break;
case 3:t=num1*num2-num1/num3;
printf("%d*%d-%d/%d=?\n",num1,num2,num1,num3);
break;
case 4:t=(num1+num2-num3)*num3/num1;
printf("(%d+%d-%d)*%d/%d=?\n",num1,num2,num3,num3,num1);
break;
}
return(t);
}
void exchange(int *p1,int *p2,int *p3)
{void swap(int *x,int *y);
if(*p1<*p2) swap(p1,p2);
if(*p1<*p3) swap(p1,p3);
if(*p2<*p3) swap(p2,p3);
}
void swap(int *x,int *y)
{int t;
t=*x;
*x=*y;
*y=t;
}
一、问题描述：
适用于小学生数学心算抢答赛。比赛题型分为两种：“四则简单运算”和“四则混合运算”，计算机随机出题，选手抢答。要求进入每种题型比赛时，计算机均有提示，每队的记分窗口随得分情况而更新。
二、功能描述：
1、显示如下画面：
2、举办单位确定参赛的队数，每队分配一个记分窗口，底分均为100分。
3、 比赛题型分为两种：“四则简单运算”（N道题）和“四则混合运算”（M道题），N、M由举办单位确定，计算机随机出题，先出“四则简单运算”题，每出一道 ，选手抢答，做对一题加5分，做错一题减5分。后出“四则混合运算”，做对一题加10分，做错一题减10分。要求进入每种题型比赛时，计算机均有提示，每队的记分窗口随得分情况而更新。
4、 根据最后总分，由高到低宣布比赛名次，按任意键退出比赛系统。
5、 要求整个设计以人为本，用户界面友好。
三、算法提示：
1、 用简单的程序设计方法
2、 一定的窗口设计技巧
3、 简单的数据类型
四、测试数据：
随机函数产生
