斐波那契数列
#include <stdio.h>void main ()
{
long int f1,f2;
int i;
f1=1,f2=2;
for(i=1;i<=20;i++)
{
printf("%121d %121d",f1,f2);
if(i%2==0)printf("\n");
f1=f1+f2;
f2=f2+f1;
}
}
2010-06-23 20:57
2010-06-23 22:20