自学C语言，大家帮忙解一道题
要求输入x的值，输出y的值
要求用switch语句解
(-5<x<0)   y=x
(x=0)      y=x-1
(0<x<10)   y=x+1

main()
{
    signed int x,y,a;
    printf("please input x:");
    scanf("%d",&x);
    if((-5<x)&&(x<0))
    a=1;
    else if(x==0)
    a=2;
    else if((0<x)&&(x<10))
    a=3;
    switch (a)
     {
         case 1:
         y=x;
         break;
         
         case 2:
         y=x-1;
         break;
         
         case 3:
         y=x+1;
         break;
         
         default:break;
     }
    printf("y is:%d",y);
 }

没有调试，基本思路就是这样了。。。
void main()
{
    signed int x,y,a;
    printf("please input x:");
    scanf("%d",&x);
    if((-5<x)&&(x<0))
      a=1;
    else
        if(x==0)
        a=2;
        else
            if((0<x)&&(x<10))
               a=3;
    switch (a)
     {
         case 1:
             printf("y=%d",x);     break;  
         case 2:
             printf("y=%d",x-1);  break;
         case 3:
              printf("y=%d",x+1);   break;
         default:
     }
}