最简单的入门问题 请教！
#include <stdio.h>void main ()
{
printf("0 & 0 is %d\n", 0 & 0);
printf("0 & 1 is %d\n", 0 & 1);
printf("1 & 1 is %d\n", 1 & 1);
printf("1 & 2 is %d\n", 1 & 2);
printf("15 & 127 is %d\n", 15 & 127);
}
最后输出结果，不解。请解释一下
#include <stdio.h>
void main ()
{
printf("0 & 0 is %d\n", 0 & 0);
printf("0 & 1 is %d\n", 0 & 1);
printf("1 & 1 is %d\n", 1 & 1);
printf("1 & 2 is %d\n", 1 & 2);
printf("15 & 127 is %d\n", 15 & 127);
}
这是&（与）符号的应用，把10进制的都转化成二进制就好了，比如1&2即为01&10，所以为0,15&127为00001111&01111111，所以为00001111，即15.
