编程，计算函数y的值。要求键盘接收自变量x的值，若x 的值不为零，则计算函数y的值并输出，再从键盘接收下一个x的值，……，直到x的值为零，则显示“Thank You，Bye!”，尔后结束程序，已知函数y与自变量x的关系为：y=3*x+10(0<x<100)
                                                                               x*x*x-20(x>=100)
# include<stdio.h>
void main()
{
int x,y;
printf("请输入x的值:",x);
scanf("%d",&x);
if(x>0 && x<100)
{y=3*x+10;
printf("y=%d",y);}
else if(x>=100)
{y=x*x*x-20;
printf("y=%d",y);}
else if(x==0)
printf("Thank you,Bye!\n");
}

　   
            　      

# include<stdio.h>
void main()
{
int x;
long int y;
printf("x de zhi :",x);
scanf("%d",&x);
while(x)
{
if(x>0 && x<100)
{y=3*x+10;
printf("y=%d",y);
}
else if(x>=100)
{y=x*x*x-20;
printf("y=%d",y);
}
else if(x==0)
{
break;}
printf("x de zhi :");
scanf("%d",&x);
}
printf("Thank you,Bye!\n");
}



有点问题   当y大于100  总是溢出   

错了   是x大于100是  总是负值

void main()
{
    int x,y;
    printf("请输入x的值:",x);
    scanf("%d",&x);
    while (1)
    {
        if(x>0 && x<100)
        {
            y=3*x+10;
            printf("y=%d\n",y);
        }
        else if(x>=100)
        {
            y=x*x*x-20;
            printf("y=%d\n",y);
        }
        else if(x==0)
        {
            printf("Thank you,Bye!\n");  
            break;
        }
        printf("请输入x的值:",x);
        scanf("%d",&x);
        getchar();
    }
}

# include<stdio.h>
void main()
{
int x,y;
printf("请输入x的值:",x);
while(1)
{
scanf("%d",&x);
if(x>0 && x<100)
{
y=3*x+10;
printf("y=%d",y);
}
else if(x>=100)
{y=x*x*x-20;
printf("y=%d",y);}
else if(x==0)
break;
}
if(x==0);
printf("thank you bye!\n");
}
你试试吧

不错

用break 或者用goto语句跳出循环