输入一个三位数整数，各个位上数的立方和相加等于其本身。输出所有符合的三位数。代码怎么写啊。。
例如abc=a*a*a+b*b*b+c*c*c=abc

不知道有没有简单的方法，笨方法就是一个一个数地检测，附合条件地则输出

using System;

class Anysis
{
    static void Main()
    {
        int[] var1 = new int[3];

        int total;

        int i, j, k;

        Console.WriteLine("Enter a value which less than thousand:");
        total = Convert.ToInt32(Console.ReadLine());

        int index = 0;

        int var2 = total;




        while (var2 != 0)    //分解出这位数字 个、十，百
        {

            var1[index] = var2 % 10;

            var2 = var2 / 10;

            index++;
        }


        i = var1[0] * var1[0] * var1[0];
        j = var1[1] * var1[1] * var1[1];
        k = var1[2] * var1[2] * var1[2];



        if ((i + j + k) == total)
            Console.WriteLine("{0} 是水仙花数", total);
        else
            Console.WriteLine("No");
        Console.ReadKey();
    }     
         

 }
。。好像这样了

for (int i = 100; i < 1000; i++)
        {
            int g = i % 10;
            int s = ((i - g) / 10) % 10;
            int b = i / 100;
            if (i == g*g*g+s*s*s+b*b*b )
            { Response.Write(i); }
        }

class Test
{
    static void main(string[] args)
    {
            for (int num = 100; num < 1000; num++)
            {
                int x = num / 100;
                int y = num / 10 % 10;
                int z = num % 10;

                double sum = Math.Pow(x, 3) + Math.Pow(y, 3) + Math.Pow(z, 3);
                if (sum == num)
                    Console.WriteLine("这是一个水仙花数：" + num);
            }
    }
}

你这是输入一个三位数求是否符合要求，但我要求的是它自动输出符合要求的结果。。
 int a, b, c, s;
            s = 100;
            do
            {


                a = s / 100;
                c = s % 100;
                b = c/10;

                c = (c-c/10*10);
                if (Math.Pow(a, 3) + Math.Pow(b, 3) + Math.Pow(c, 3) == s)
                    Console.WriteLine(s);
                s++;

            }
            while (s < 1000);

楼主好像你要的就是“输入一个三位数整数”得出是不是水仙花数。。
呵呵
int a, b , c ;
            for (a = 0; a <= 9;a++ )
                for (b = 0; b<= 9; b++)
                    for (c = 0; c <= 9;c++)if (a * a * a + b * b * b + c * c * c == 100 * a + 10 * b + c && 100 * a + 10 * b + c >= 100 && 100 * a + 10 * b + c <= 999)
{ Console.WriteLine("{0}{1}{2}", a, b, c); }

我遇到了相似的题目，不过是求21的，输出所有的21位的数，要求每一位的21次方的和加起来等于这个数，答案在3分钟之内解出，怎么写呀？