double sum = 0;
    int tmp = 0;
    int i = 0;
    while ( 1 )
    {
        printf("please input a number： ");
        scanf("%d",&tmp);
        if ( tmp ==0 )
            break;
        else if (tmp<0)
        {
            printf("only positive numbers are accepted\n");
        }
        continue;
        sum += tmp;
        i++;
    }


    printf("the average is %0.2lf",sum/i );

    return 0;
}
请问大大，哪里有问题
输入2 2 -1 0
结果很奇怪。。the average is -1.#J

continue;语句每次都被执行，导致
sum += tmp;
i++;
永远被跳过。

#include <stdio.h>
int main( void )
{
double sum = 0;
    int tmp = 0;
    int i = 0;
    while ( 1 )
    {
        printf("please input a number： ");
        scanf("%d",&tmp);
        if ( tmp ==0 )
            break;
        else if (tmp<0)
        {
            printf("only positive numbers are accepted\n");
               continue;//放进来！！
        }
        
        sum += tmp;
        i++;
    }


    printf("the average is %0.2lf",sum/i );

    return 0;
}

#include <stdio.h>
#include <stdlib.h>
int main( void )
{
double sum = 0;
    int tmp = 0;
    int i = 0;
    while ( 1 )
    {
        printf("please input a number： ");
        fflush( stdin );
        scanf("%d",&tmp);
        if ( tmp ==0 )
            break;
        else if (tmp<0)
        {
            printf("only positive numbers are accepted\n");
               continue;
        }
        
        sum += tmp;
        i++;
    }


    printf("the average is %0.2lf",sum/i );

    return 0;
}

这样程序会更好，但2 2 -1等请一个个输入。

2楼正解