好  那谢了

18楼的对呀  你从试试

#include <stdio.h>
void main()
{
  float I,Q;int t;
  scanf("%f",&I);
  if(I<0)printf("it is not right\n");
  else{
       if(I>=1000000)Q=0.1*100000+0.075*100000+0.05*200000+0.03*200000+0.015*400000+0.01*(I-1000000);   
       else t=I/100000;
       switch(t)
         {  
           case 0:Q=0.1*I;break;
           case 1:Q=0.1*100000+0.075*(I-100000);break;
           case 2:
           case 3:Q=0.1*100000+0.075*100000+0.05*(I-200000);break;
           case 4:
           case 5:Q=0.1*100000+0.075*100000+0.05*200000+0.03*(I-400000);break;
           case 6:
           case 7:
           case 8:
           case 9:Q=0.1*100000+0.075*100000+0.05*200000+0.03*200000+0.015*(I-1000000);break;
         }
    printf("Q=%f\n",Q);
}
}

这个在VC上可以运行，楼主有几个字母和括号是全角，所以不能运行

还是没人帮我改对    我在   其他的机子上重新运行了的        不行

我自己改过来了   在大家的帮助下   以后多交流啊
#include<stdio.h>
void main()
{
  double I,Q;int t;
  scanf("%lf",&I);
  if(I<0)printf("it is not right);
  else
      {
        t=I/100000;
        switch(t)
       { case 0:Q=0.1*I;break;
         case 1:Q=0.1*100000+0.075*(I-100000);break;
         case 2:
         case 3:Q=0.1*100000+0.075*100000+0.05*(I-200000);break;
         case 4:
         case 5:Q=0.1+100000+0.075*100000+0.05*200000+0.03*(I-400000);break;
         case 6:
         case 7:
         case 8:
         case 9:Q=0.1*100000+0.075*100000+0.05*200000+0.03*200000+0.015*(I-600000);break;
       }
     if(t>=10)Q=0.1*100000+0.075*100000+0.05*200000+0.03*200000+0.015*400000+0.01*（I-1000000);
    printf("Q=%Lf\n",Q);
  }




}

我都有运行下才拿上来的额