要求输出下列这个菜单：

       主菜单
=====================
1.输入学生成绩
2.查询学生成绩
3.打印输出成绩
0.退出系统
=====================
请选择（1-5):


如果选择1，则显示“请输入”；选择2，则显示“请输入查找学生学号”；选择3，显示“正在输出”；选择0，显示“谢谢使用”；选择其它则显示“输入错误，请重新输入”。
用循环语句实现用户的重复输入，直到输入选择为“0”是，结束循环。



#include <stdio.h>

void main()
{
        int num,choice;
        do
        {
           printf("Menu%-6\n1.Put in students results\n2.Inquire students results\n3.Print out result\n0.Exit\n");
           printf("Please choose(0-3):");
           scanf("%d",&num);
            switch(choice 3)
                 {
                   case 1: printf("Please enter\n"); break;
                   case 2: printf("Please enter the student number\n"); break;
                   case 3: printf("Printing!\n"); break;
                   default: printf("Input wrong!");
                 }
         }
       while (num=0);
           print("Thank you");
               
        


}


检查时总是提示我缺少“）”在scanf("%d",&num);中。。。我觉得不是这个问题，麻烦大家帮忙看一下错哪儿了。谢谢

switch(choice 3)
应该是switich(num);

printf("Thank you");//你打错了

谢谢LS两位指点。但是现在的情况是，我输入1至3，在出现相应选项的同时，“Thank you!”也跟在最后出现了。我改如何修改可以让程序保持在swith那个循环里，直到我个人输入0时才显示"Thank you!"?

我一下也没想起来，再等等............

这样行不
#include <stdio.h>
void main()
{
        int num,choice;   
           printf("Menu%-6\n1.Put in students results\n2.Inquire students results\n3.Print out result\n0.Exit\n");
           printf("Please choose(0-3):");
           scanf("%d",&num);
            switch(choice=num)
                 {  
                   case 0:printf("Thank you\n");break;
                   case 1: printf("Please enter\n"); break;
                   case 2: printf("Please enter the student number\n"); break;
                   case 3: printf("Printing!\n"); break;
                   default: printf("Input wrong!");break;
                 }
 
}

可以，但是强调使用do-while语句。。。所以我认为应该在1-3做一个循环。。。但就是不知道该如何做。。。

可以尝试着改成用if else
你这样试试

#include <stdio.h> 
 
void main() 
{ 
        int num,choice; 
         
        { 
           printf("Menu%-6\n1.Put in students results\n2.Inquire students results\n3.Print out result\n0.Exit\n"); 
           printf("Please choose(1-3):"); 
           scanf("%d",&num); 
           if(num>=1) 
           {switch(num) 
                 {  
                   case 1: printf("Please enter\n"); break; 
                   case 2: printf("Please enter the student number\n"); break; 
                   case 3: printf("Printing!\n"); break; 
                   default: printf("Input wrong!"); 
                 } 
              } 
            else 
       printf("Thank you"); 
               } 

看这行不
#include <stdio.h>

void main()
{
        int choice,i;


           printf("Menu%-6\n1.Put in students results\n2.Inquire students results\n3.Print out result\n0.Exit\n");
           for(i=0;i<4;i++)
           {
              printf("Please choose(0-3):");
              scanf("%d",&choice);
              if(choice==0)
              {
                 printf("thank you!\n");
              }
              if(choice==1)
              {
                 printf("please ehter \n") ;
              }
              if(choice==2)
              {
                 printf("Please enter the student number\n");
              }
              if(choice==3)
              {
                 printf("Printing!");
              }
           }

}

应该是 while(num=0); 这一段多个“；”