public class c{
     public static int getNum(double num1,double num2){
         
            int s=(int)num1+(int)(Math.random()*(num2-num1));
            if(s%2==0){
              return s;
            }
             else
                return s+1;
            }
       public static void main(String args[]){
           
         
           /System.out.println(" "+getNum(2,32));                          
                         }         
}

 



上面是结果是输出2到32随机一个偶数

请问如何可以输出其中6个偶数，并且求和呢？？？

int sum = 0;
int x = 0;
for (int i=0; i<6; i++) {
    x = getNum(2, 32);
    System.out.println(x);
    sum += x;
}

先谢谢了

public static double random()
大于等于 0.0 且小于 1.0 的伪随机 double 值。

我情愿去产生一个1到16的数再去*2

版主说的对。。
import java.util.Random;

public class c {
    private static Random rand = new Random();

    public static int getNum(int num1, int num2) {
        int s = num1 / 2 + (rand.nextInt(num2 / 2 - num1 / 2 + 1));
        return 2 * s;
    }

    public static void main(String args[]) {
        int sum = 0,tep;
        for(int i = 0;i<6;i++){
            tep = getNum(2,32);
            System.out.print(" "+tep);
            if(i<5)
                System.out.print(" +");
            sum += tep;
        }
        System.out.println(" = " + sum);
    }
}

math.random()的默认值是0～1中的double数吗？
请教一下！

math.random()的默认值是0。1～1。0中的double数