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标题:C词法分析,以小程序试验可以,大点的就缺些数据?
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shiyuanren
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C词法分析,以小程序试验可以,大点的就缺些数据?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
char c,a[30],b[20];
int i=0,count0=0,count1=0,count2=0,count3=0,count5=0;
bool flag=true;
FILE *fp1,*fp2;
   char *key[]={" ","auto","bool","break","case","char","complex","const","continue","default","restrict","do","double",
                 "else","enum","extern","float","for","goto","if","imaginary","inline","int","long","register",
                 "return","short","signed","sizeof","static","struct","switch","typedef",
                 "union","unsigned","void","volatile","while","#define","#include"};     /*C语言所有关键字,共37个*/
    char *oper[]={" ","!","%","^","&","*","-","+","=","~","|",".",
                   "<",">","/","?",":","+=","-=","*=","/=","%=","<<==",">>==","|=","->","++",
                  "--","<<",">>","<=",">=","==","!=","&&","||"};/*运算符*/
    char *sep[]={" ","#","(",")","[","]","\'",";",":","\"","{","}",",","\\"," "};/*分隔符*/
/************************
    是否为保留字
************************/
int iskey(char *a){                                       
    for(i=1;i<40;i++)    
        if(strcmp(a,key[i])==0){
            fprintf(fp2,"0\t\t\t%d\t\t\t%s\n",i,a);
            return 1;
        }
        return 0;
}
/**************************
    是否为运算符
***************************/
void isoper(char *a){
    for(i=1;i<35;i++)
        if(strcmp(a,oper[i])==0){
            fprintf(fp2,"2\t\t\t%d\t\t\t%s\n",i,a);
        }
}
/************************
    是否为分隔符
************************/
void issep(char *a){                                       
    for(i=1;i<14;i++)
        if(strcmp(a,sep[i])==0){
        fprintf(fp2,"1\t\t\t%d\t\t\t%s\n",i,a);
        }    
}
/*是否为标识符*/
void issyb(char *a){
    FILE *fp0;    
    int k;
    k=strlen(a);
    if(((a[0]>='A')&&(a[0]<='Z'))||((a[0]>='a')&&(a[0]<='z'))||(a[0]=='_')){
        for(i=1;i<k-1;i++){
           if(((a[i]<48||a[i]>122)||(a[i]>57&&a[i]<65)||(a[i]>90&&a[i]<97))&&(a[i]!='_'))
               flag=false;
               continue;
        }
       if(flag==true){
               count5++;
               fp0=fopen("bzf.txt","a");
                fprintf(fp0,"%s\t\t\t3\t\t\t%d\n",a,count5);
                fclose(fp0);
                fprintf(fp2,"3\t\t\t%d\t\t\t%s\n",count5,a);
       }
    }
}
/**********************
 是否为整型或浮点型常量
***********************/
void isdigit(char *a){
    FILE *fp6;    
    if((a[0]>='0')&&(a[0]<='9')){
        for(i=0;i<100;i++){
            if(a[i]=='.')
                flag=false;
            continue;}
            if(flag==false){                                    /*浮点型常量输出*/
                fp6=fopen("cl.txt","a");
                count1++;
                fprintf(fp6,"%s\t\t\t4\t1\t\t%d\n",a,count1);
                fclose(fp6);
                fprintf(fp2,"4\t\t\t1\t%d\t\t%s\n",count1,a);
            }
            else{                                            /*整型常量*/
                fp6=fopen("cl.txt","a");
                count0++;
                fprintf(fp6,"%s\t\t\t4\t0\t\t%d\n",a,count0);
                fclose(fp6);
                fprintf(fp2,"4\t\t\t0\t%d\t\t%s\n",count0,a);
            }
        
        
    }
    
}
/***********************************
    字符、字符串常量判断
************************************/
void ischar(char *a){
    FILE *fp6;
    int k;
    k=strlen(a);
    if(((a[1]>='A')&&(a[1]<='Z'))||((a[1]>='a')&&(a[1]<='z'))||(a[1]=='_')){
        fp6=fopen("cl.txt","a");
        if((a[0]=='\'')&&(a[2]=='\'')){                              /*是字符常量*/
                
                count2++;
             fprintf(fp6,"%s\t\t\t4\t2\t\t%d\n",a,count2);
                
             fprintf(fp2,"4\t\t\t2\t%d\t\t%s\n",count2,a);
      }
        else
            if((a[0]=='\"')&&(a[k-1]=='\"')){                         /*是字符串常量*/  
                
                count3++;
             fprintf(fp6,"%s\t\t\t4\t3\t\t%d\n",a,count3);
            
             fprintf(fp2,"4\t\t\t3\t%d\t\t%s\n",count3,a);
        }
        fclose(fp6);
    }
}
/******************************
     分割单词
******************************/
void cut(){
    int j;
    while(!feof(fp1)){
        do{
            a[i++]=fgetc(fp1);
        }while(a[i-1]!='\0'&&a[i-1]!='\n'&&a[i-1]!=' '&&a[i-1]!=EOF&&a[i-1]!='+'&&a[i-1]!='-'&&a[i-1]!='*'&&a[i-1]!='/'
            &&a[i-1]!='%'&&a[i-1]!='='&&a[i-1]!='('&&a[i-1]!=')'&&a[i-1]!='{'&&a[i-1]!='}'&&a[i-1]!='>'&&a[i-1]!='<'&&
            a[i-1]!='|'&&a[i-1]!='&'&&a[i-1]!=';'&&a[i-1]!=','&&a[i-1]!='['&&a[i-1]!=']');
        if(a[i-1]=='\0'|| a[i-1]=='\n'||a[i-1]==' '|| a[i-1]==EOF){
        a[i-1]=0;
        j=iskey(a);
        isoper(a);
        issep(a);
        if(j==0){
            issyb(a);
        }
        j=0;
        isdigit(a);
        ischar(a);
        
        }
        if(a[i-1]=='+'||a[i-1]=='-'||a[i-1]=='*'||a[i-1]=='/'
            ||a[i-1]=='%'||a[i-1]=='='||a[i-1]=='('||a[i-1]==')'||a[i-1]=='{'||a[i-1]=='}'||a[i-1]=='>'||a[i-1]=='<'
            ||a[i-1]=='|'||a[i-1]=='&'||a[i-1]==';'||a[i-1]==','||a[i-1]=='['||a[i-1]==']') {    
               b[0]=a[i-1];
                
               a[i-1]=0;
               j=iskey(a);
               isoper(a);
               issep(a);
               if(j==0){
                  issyb(a);}
               j=0;
               isdigit(a);
               ischar(a);
if(b[0]=='='||b[0]=='+'||b[0]=='-'||b[0]=='>'||b[0]=='<'||b[1]=='|'||b[1]=='&'){
  b[1]=fgetc(fp1);
  if(b[1]=='='||b[1]=='+'||b[1]=='-'||b[1]=='<'||b[1]=='>'||b[1]=='|'||b[1]=='&'){
   b[2]=0;
   isoper(b);
  }
  else{
      ungetc(b[1],fp1);
      b[1]=0;
      issep(b);
      isoper(b);
}}
 else{
      b[1]=0;
      issep(b);
      isoper(b);
  }

              

        }
        if(a[i]=='\0'||a[i]=='\n'||a[i]==' '||a[i-1]!=EOF||a[i-1]=='+'||a[i-1]=='-'||a[i-1]=='*'||a[i-1]=='/'
            ||a[i-1]=='%'||a[i-1]=='='||a[i-1]=='('||a[i-1]==')'||a[i-1]=='{'||a[i-1]=='}'||a[i-1]=='>'||a[i-1]=='<'
            ||a[i-1]=='|'||a[i-1]=='&'||a[i-1]==';'||a[i-1]==','||a[i-1]=='['||a[i-1]==']')                   /*有问题*/
            i=0;
        for(j=0;j<=i-1;j++)
            a[j]=0;
    
    }

}
/*各表初始化程序*/
void init()
{            
   
    FILE *fp;
    int i;
    char c;
    fp=fopen("blz.txt","w");        /*初始化保留字表*/
    for(i=1;i<=39;i++){
        if(i<=9)
          fprintf(fp,"%-20s 0  0%d\n",key[i],i);
        else
          fprintf(fp,"%-20s 0  %2d\n",key[i],i);
    }
    fclose(fp);               
    fp=fopen("fgf.txt","w");        /*初始化限制符表*/
    for(i=1;i<=13;i++){
        if(i<=9)
         fprintf(fp,"%-20s  1  0%d\n",sep[i],i);
        else
          fprintf(fp,"%-20s  1  %2d\n",sep[i],i);
    }
    fclose(fp);               
    fp=fopen("ysf.txt","w");        /*初始化运算符表*/
    for(i=1;i<=35;i++){
        if(i<=9)
          fprintf(fp,"%-20s 2  0%d\n",oper[i],i);
        else
          fprintf(fp,"%-20s 2  %2d\n",oper[i],i);
    }
    fclose(fp);               
      
    c='"';
    fprintf(fp,"%c\n",c);
    fclose(fp);              
    fp=fopen("bzf.txt","w");       /*初始化标识符表*/
    fclose(fp);              
    fp=fopen("cl.txt","w");       /*初始化常数表*/
    fclose(fp);               
    fp=fopen("output.txt","w");  /*初始化输出文件*/
    fclose(fp);              
}
void main()
{     
     init();
     fp1=fopen("input.txt","r");
     fp2=fopen("output.txt","w");
     cut();
     fclose(fp1);
     fclose(fp2);
}
搜索更多相关主题的帖子: c词法分析 
2009-08-17 20:12
airhiphop
Rank: 4
来 自:江苏南通
等 级:业余侠客
帖 子:69
专家分:256
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得分:14 
最近闲来也无聊,就拿你的这个东西开刀吧.看你发了好几个帖了,我今晚开始去研究研究

看代码有点头晕,能详细介绍下你要实现的东西么??

[ 本帖最后由 airhiphop 于 2009-8-18 08:19 编辑 ]

2009-08-18 08:14
快速回复:C词法分析,以小程序试验可以,大点的就缺些数据?
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