一个小问题,望指教,谢谢
代码如下:
#include "stdafx.h"
#include "conio.h"
#include "string.h"
#include   <cstdio>
int main(int argc, char* argv[])
{
        char a[3] ; int count = 0,k;
s1:
        printf("进入系统请输入y,退出请按n\n");
        for(int i=0;;i++)
        {
                switch(getch())
                {
                case 'y':
                        {
                                printf("\n请输入1-10进行选择\n");        
                                scanf("%d",&k);
                            fflush(stdin);
                                if(k>0&&k<11)
                                {
                                        strcpy(a,"abc");
                                        count++;
                                        printf("\n继续请输入Y,退出请按n\n");
                                }
                                else
                                {
                                        printf("你的输入有误,请重新输入\n");
                                        goto s1;
                                       
                                }
                        }
                        break;
                case 'n':goto s2;        break;
                default :
                        {
                                printf("你的输入有误,请重新输入\n");
                                goto s1;
                        }        
                        
                }
        }


s2:
        printf("\n您的输入为:\n\n\n");
        printf("^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\n");
        
        for( i=0;i<count;i++)
        {
                printf("%d.%s                                       \n",i+1,a);
        }
        printf("^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\n");

return 0;
}
问题是进入那个选数之后,当输入数字之后再输入字符它不会报错(而当第一次输入的是字符它就会转到"你的输入有误,请重新输入"),  而且那个count还会继续累加,打印也一样.请问应该怎么解决

/************************************************************

        你写的是C++，不太熟悉。不过我想可能是没清除键盘
    缓存区的原因，因为我遇到过类似现象。

        现加上红色代码部分，请运行调试，谨作参考。

**************************************************************/
#include "stdafx.h"
#include "conio.h"
#include "string.h"
#include   <cstdio>
#define X {char c;while(c=getchar()!='\n');}
int main(int argc, char* argv[])
{
        char a[3] ; int count = 0,k;
s1:
        printf("进入系统请输入y,退出请按n\n");
        for(int i=0;;i++)
        {
                switch(getch())
                {
                case 'y':
                        {
                                printf("\n请输入1-10进行选择\n");        
                                scanf("%d",&k);
                               X;
                            fflush(stdin);
                                if(k>0&&k<11)
                                {
                                        strcpy(a,"abc");
                                        count++;
                                        printf("\n继续请输入Y,退出请按n\n");
                                }
                                else
                                {
                                        printf("你的输入有误,请重新输入\n");
                                        goto s1;
                                       
                                }
                        }
                        break;
                case 'n':goto s2;        break;
                default :
                        {
                                printf("你的输入有误,请重新输入\n");
                                goto s1;
                        }        
                        
                }
        }


s2:
        printf("\n您的输入为:\n\n\n");
        printf("^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\n");
        
        for( i=0;i<count;i++)
        {
                printf("%d.%s                                       \n",i+1,a);
        }
        printf("^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\n");

return 0;
}

谢咯.不过我自己已经搞定了,把字符强制转换成相对应的数字的ASCII码就行了

switch(getch())


好吝啬  一个 变量都不放....